<span>11,550 km has to be changed to 11,550,000 meters
G · m · t² = 4 · π² · r³ we can change that to
</span>t² = (4 · π² · r³) / <span>(G · m )
t^2 = 4*PI^2*r^3 / (G*m)
</span>t^2 = 4*PI^2*<span>(11,550,000)^3 / 6.67*10^-11*5.98*10^24kg
t^2 = </span>
<span>
<span>
<span>
6.083*10^22
</span>
</span>
</span>
<span><span>
</span>
</span>
/
<span>
<span>
<span>
3.9</span></span></span>9 * 10^14
t^2 =
<span>
<span>
<span>
152,500,000</span></span></span>
t = <span>12,350 seconds
</span>and its orbital distance it travels is 11,550 * 2*PI = 70,050 kilometers
Therefore, it is traveling at 70,050 km / 12,350 second which equals
5.67 km per second which <em>is 5,670 meters per second.</em>
Source:
http://www.1728.org/kepler3a.htm
The expression for the distance the car travels after t seconds is d = 200t + 50t²
<h3>Equation of motion </h3>
From the question, we are to write an expression for the distance the car travels after t seconds
From the given information,
The equation for the motion of an object with constant acceleration is
d = vt + 0.5at²
For the race car,
v = 200 ft/s
a = 100 ft/s²
Putting the parameters into the equation, we get
d = 200t + 0.5(100)t²
d = 200t + 0.5 ×100)t²
d = 200t + 50t²
Hence, the expression for the distance the car travels after t seconds is d = 200t + 50t²
Learn more on Equations of motion here: brainly.com/question/20910641
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