Answer: ![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)
Step-by-step explanation:
First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;
Divide by m to isolate 
.
To eliminate the square and isolate v, extract the square root.
![\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3D%5Csqrt%5B%5D%7Bv%5E2%7D)
![\sqrt[]{\frac{2K}{m} }=v](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3Dv)
let's rewrite it in a way that v is in the left side.
Answer:
y=-2x-5
Step-by-step explanation:
y-y1=m(x-x1)
y-(-7)=-2(x-1)
y+7=-2x+2
y=-2x+2-7
y=-2x-5
T= Mins
1 hour = 60 mins
60 x 6 = 360
360 - T = x
X= How many minutes he has remaining
- The answer is <u>0</u><u>.</u>
- LHS = RHS, hence verified.
<u>Value of x (substitute 0 in the place of x).</u>
- So, value of x is <u>0</u><u>.</u>
Answer:
The net perfect number would be 28
Step-by-step explanation:
When you add up all the factors of 28 (other than 28) you get 28.
1 + 2 + 4 + 7 + 14 = 28
