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Ganezh [65]
3 years ago
9

During a sale, for each shirt that Mark purchased at the regular price, he also purchased a shirt at half the regular price. How

many shirts did Mark purchase during the sale?
A) The regular price of each of the shirts that Mark purchased during the sale was $21.50.
B) The total of the prices for all the shirts that Mark purchased during the sale was $129.00.
Mathematics
1 answer:
Arisa [49]3 years ago
4 0
I think the answer is b hope i helped
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Can someone answer this question for me?
hjlf

Answer:

That is a right angles triangle which means to get the area: multiply the base(14.1)to be the height (9.8) divided by 2.

Formula : half the base times the height given. Your answer is to be squared and don't forget the correct unit.

6 0
3 years ago
Combine terms/simolify
-Dominant- [34]

Answer:

\dfrac{2m -1}{5}

Step-by-step explanation:

Since we have common denominators inside the parentheses, we can combine the denominators. Then, we get the following expression:

2\huge\text{(}\dfrac{1}{5} m - \dfrac{2}{5} \huge\text{)} + \dfrac{3}{5}

2\huge\text{(}\dfrac{m - 2}{5} \huge\text{)} + \dfrac{3}{5}

Now, we can multiply the expression inside the parentheses by 2.

\huge\text{(}\dfrac{2m - 4}{5} \huge\text{)} + \dfrac{3}{5}

Since the expression inside the parentheses cannot be <u>simplified further</u>, we can open the parentheses and simplify the expression.

\dfrac{2m - 4}{5}  + \dfrac{3}{5}

We can combine the denominators as the denominators are the same.

\dfrac{2m - 4 + 3}{5}

Finally, we can simplify -4 + 3.

\dfrac{2m -1}{5}

Therefore, the simplified expression is (2m - 1)/5.

Learn more about combining like terms: brainly.com/question/13080103

5 0
2 years ago
Your English teacher has given you a list of 10 possible topics for essays. You need to pick four topics from the list to write
-Dominant- [34]
10-12 i think, because 10*4=40 and 12*4=48

8 0
3 years ago
Find the absolute maximum and minimum values of f(x, y) = x+y+ p 1 − x 2 − y 2 on the quarter disc {(x, y) | x ≥ 0, y ≥ 0, x2 +
Andreas93 [3]

Answer:

absolute max: f(x,y)=1/2+p1 ; at P(1/2,1/2)

absolute min: f(x,y)=p1 ; at U(0,0), V(1,0) and W(0,1)

Step-by-step explanation:

In order to find the absolute max and min, we need to analyse the region inside the quarter disc and the region at the limit of the disc:

<u>Region inside the quarter disc:</u>

There could be Minimums and Maximums, if:

∇f(x,y)=(0,0) (gradient)

we develop:

(1-2x, 1-2y)=(0,0)

x=1/2

y=1/2

Critic point P(1/2,1/2) is inside the quarter disc.

f(P)=1/2+1/2+p1-1/4-1/4=1/2+p1

f(0,0)=p1

We see that:

f(P)>f(0,0), then P(1/2,1/2) is a maximum relative

<u>Region at the limit of the disc:</u>

We use the Method of Lagrange Multipliers, when we need to find a max o min from a f(x,y) subject to a constraint g(x,y); g(x,y)=K (constant). In our case the constraint are the curves of the quarter disc:

g1(x, y)=x^2+y^2=1

g2(x, y)=x=0

g3(x, y)=y=0

We can obtain the critical points (maximums and minimums) subject to the constraint by solving the system of equations:

∇f(x,y)=λ∇g(x,y) ; (gradient)

g(x,y)=K

<u>Analyse in g2:</u>

x=0;

1-2y=0;

y=1/2

Q(0,1/2) critical point

f(Q)=1/4+p1

We do the same reflexion as for P. Q is a maximum relative

<u>Analyse in g3:</u>

y=0;

1-2x=0;

x=1/2

R(1/2,0) critical point

f(R)=1/4+p1

We do the same reflexion as for P. R is a maximum relative

<u>Analyse in g1:</u>

(1-2x, 1-2y)=λ(2x,2y)

x^2+y^2=1

Developing:

x=1/(2λ+2)

y=1/(2λ+2)

x^2+y^2=1

So:

(1/(2λ+2))^2+(1/(2λ+2))^2=1

\lambda_{1}=\sqrt{1/2}*-1 =-0.29

\lambda_{2}=-\sqrt{1/2}*-1 =-1.71

\lambda_{2} give us (x,y) values negatives, outside the region, so we do not take it in account

For \lambda_{1}: S(x,y)=(0.70, 070)

and

f(S)=0.70+0.70+p1-0.70^2-0.70^2=0.42+p1

We do the same reflexion as for P. S is a maximum relative

<u>Points limits between g1, g2 y g3</u>

we need also to analyse the points limits between g1, g2 y g3, that means U(0,0), V(1,0), W(0,1)

f(U)=p1

f(V)=p1

f(W)=p1

We can see that this 3 points are minimums relatives.

<u>Conclusion:</u>

We compare all the critical points P,Q,R,S,T,U,V,W an their respective values f(x,y). We find that:

absolute max: f(x,y)=1/2+p1 ; at P(1/2,1/2)

absolute min: f(x,y)=p1 ; at U(0,0), V(1,0) and W(0,1)

4 0
3 years ago
Find the volume of the Firgure
Andrej [43]
The answer is of the figure is 24
7 0
3 years ago
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