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2 years ago

Another question Use the given formula to find the area of the given rectangle: A=L x W

Mathematics

2 answers:

ludmilkaskok [199]2 years ago

8 0

A=LxW so 36*23=828 and that is why 828 is the answer

Scrat [10]2 years ago

7 0

Answer:

Step-by-step explanation:

A=L x W So.. 36m x 23m = 828m Hope this helps

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Write two numbers that multiply to the value on top and add to the value on the bottom.

sattari [20]

Answer:

6 and 2

Step-by-step explanation:

6 times 2 is 12 and 6 plus 2 is 8

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2 years ago

You need to buy new soil for your garden. Find the area of the garden. Use the dimensions shown in the picture.

Lubov Fominskaja [6]

Answer:

95 square meters

Step-by-step explanation:

I am answering this question assuming 19 is the base because it is the longest side on the triangle. (there is no picture provided)

The formula for area of triangle is base * height * 1/2

So 19 * 10 *1/2 is 95.

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2 years ago

Wha it is 2,200 divided by 30 and 2,300 divided by 30

Paladinen [302]

Answer:

2,200/30=73.3333333

2,300/30=76.6666667

Step-by-step explanation:

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2 years ago

Read 2 more answers

Suppose a student reaches in the bag and randomly selects nine red chips and eleven yellow chips. Based on this sample, what is

nataly862011 [7]

Answer:

There are more boys than girls. The red chips are girls are the boy are the yellow chips. If more yellow chips were pulled out then there are more boys. 11 + 9 = 2. 10 + 9 = 19 + 1 = 20. The fraction of how many boys there are would be 11/21 and the fraction for girls would be 9/21. Also 11 x 9 = 99. There would be 99 people if you times the number of girls and boys. But it's best to add because it would be in the smaller form if you were to times it.

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2 years ago

Name two solutions for each inequality.

ahrayia [7]

So,

#1: $n \geq 3 \frac{11}{16} + 4 \frac{1}{2}$

Convert to like improper fractions.
$n \geq \frac{59}{16} + \frac{72}{16}$

Add.
$n \geq \frac{131}{16}\ or\ 8 \frac{3}{16}$

So, one solution could be $8 \frac{3}{16}$ .

Another solution could by 9. There is also 10, 11, 12, etc., and all numbers in between.

#2: $k \ \textless \ 6 \frac{2}{5} * 15$

Convert into improper fraction form.
$k \ \textless \ \frac{32}{5} * 15$

Multiply.
$\frac{(2^5)(3)(5)}{5}$

Cross-cancel, and we have our final result.
$(2^5)(3) = 96$
k < 96

96 is not a solution.

95 is a solution.

So is 94, 93, 92, etc, and all numbers in between.

6 0

2 years ago