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MariettaO [177]
2 years ago
7

Have 15 minutes please help!!

Mathematics
1 answer:
Marina86 [1]2 years ago
3 0
Anything which have their degree as 0 is always equal to 1
=> 5^0=1
Option 3 is the answer..!!
Hope this helps you!!

Good Luck!
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I need help<br> On this question
Lyrx [107]
Answer:
B-28+19m

Explanation:
3 0
2 years ago
Find the area of the part of the plane 3x 2y z = 6 that lies in the first octant.
gavmur [86]

The area of the part of the plane 3x 2y z = 6 that lies in the first octant  is  mathematically given as

A=3 √(4) units ^2

<h3>What is the area of the part of the plane 3x 2y z = 6 that lies in the first octant.?</h3>

Generally, the equation for is  mathematically given as

The Figure is the x-y plane triangle formed by the shading. The formula for the surface area of a z=f(x, y) surface is as follows:

A=\iint_{R_{x y}} \sqrt{f_{x}^{2}+f_{y}^{2}+1} d x d y(1)

The partial derivatives of a function are f x and f y.

\begin{aligned}&Z=f(x)=6-3 x-2 y \\&=\frac{\partial f(x)}{\partial x}=-3 \\&=\frac{\partial f(y)}{\partial y}=-2\end{aligned}

When these numbers are plugged into equation (1) and the integrals are given bounds, we get:

&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{(-3)^{2}+(-2)^2+1dxdy} \\\\&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{14} d x d y \\\\&=\sqrt{14} \int_{0}^{2}[y]_{0}^{3-\frac{3}{2} x} d x d y \\\\&=\sqrt{14} \int_{0}^{2}\left[3-\frac{3}{2} x\right] d x \\\\

&=\sqrt{14}\left[3 x-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3.2-\frac{3}{2} \cdot \frac{1}{2} \cdot 3^{2}\right] \\\\&=3 \sqrt{14} \text { units }{ }^{2}

In conclusion,  the area is

A=3 √4 units ^2

Read more about the plane

brainly.com/question/1962726

#SPJ4

5 0
1 year ago
Simplify ( 8∙4∙2 8∙7 )^2 × ( 8 0 7−3 )^3 × 7 −9 .
stich3 [128]

\bf ~\hspace{7em}\textit{negative exponents}&#10;\\\\&#10;a^{-n} \implies \cfrac{1}{a^n}&#10;~\hspace{4.5em}&#10;a^n\implies \cfrac{1}{a^{-n}}&#10;~\hspace{4.5em}&#10;\cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m}&#10;\\\\[-0.35em]&#10;\rule{34em}{0.25pt}\\\\&#10;\left( \cfrac{8\cdot 4\cdot 2}{8\cdot 7} \right)^2\times \left( \cfrac{8^0}{7^{-3}} \right)^3\times 7^{-9}\implies \left( \cfrac{8\cdot 8}{8\cdot 7} \right)^2\times \left( \cfrac{1\cdot 7^3}{1} \right)^3\times \cfrac{1}{7^9}


\bf \left( \cfrac{8}{8}\cdot \cfrac{8}{7} \right)^2\times (7^3)^3\times \cfrac{1}{7^9}\implies \left( \cfrac{8}{7} \right)^2\times 7^{3\cdot 3}\times \cfrac{1}{7^9}\implies \cfrac{8^2}{7^2}\times \cfrac{7^9}{7^9}&#10;\\\\\\&#10;\cfrac{8^2}{7^2}\implies \cfrac{64}{49}

4 0
3 years ago
Given that f ( x ) = 8 x + 5 f ( x ) = 8 x + 5 and g ( x ) = 3 − x 2 g ( x ) = 3 - x 2 , calculate f(g(0))
Alex17521 [72]

Answer:

29

Step-by-step explanation:

g(0)=3-2(0)

     = 3

f(3) = 8(3)+5

f(3) = 29

5 0
2 years ago
Mia is mixing nuts and cereal squares to make
Harman [31]

Answer:

TO MAKE A NUTTY CEREAL ........

6 0
2 years ago
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