There are a few options we can take. One way is to use the tangent ratio to tie together the opposite and adjacent sides, and then apply the inverse tangent (aka arctangent) to get the angle itself.
Let x be the upper left acute angle, and y be the lower right acute angle.
We can say
tan(angle) = opposite/adjacent
tan(x) = 16/5
x = arctan(16/5)
x = 72.645975 approximately
x = 72.6
and also
tan(angle) = opposite/adjacent
tan(y) = 5/16
y = arctan(5/16)
y = 17.3540246
y = 17.4
Note how x+y = 72.6+17.4 = 90. The two acute angles of any right triangle are complementary, meaning they always add to 90. So if you found x, then you can compute y = 90-x without needing the tangent ratio.
Your calculator needs to be in degree mode when using the arctangent function, which is denoted as
on many graphing calculators.
Answer:
![\sqrt{97} \\](https://tex.z-dn.net/?f=%5Csqrt%7B97%7D%20%5C%5C)
Step-by-step explanation:
9^2 + 4^2 = X^2
81+16 = x^2
x^2 = 97
x = ![\sqrt{97} \\](https://tex.z-dn.net/?f=%5Csqrt%7B97%7D%20%5C%5C)
Answer:
Answer below
Step-by-step explanation:
If you mean constant of proportianality, that is just basically the unit rate. If you have point on the graph, you probably want to write down their coordinates. once you do that you see if the line are going up right diagonally or left diagonally. once you do that, you going to want to take the y coordinate from the highest point on the graph and subtract the y from the lowest point on the graph. repeat for x. finally, put the y answer over the x over to create a fraction. if you can make it a whole number do that, but most teachers won't want you to convert it to a mixed number.
I hope I answered what you were actually asking for lol.
X^2+3x+12
3x^2-5x-2
X^2+4x+9