4 pages Elena = 5 pages Jada
To figure out how many pages Jada reads if Elena reads 1, divide 5 by 4: 1.25. This means that for every 1 page Elena reads, Jada reads 1.25 pages.
So if Elena reads 9 pages, multiply 1.25 by 9: 11.25 pages that Jada reads.
For S pages read by Elena, this is a variable, so I’m assuming it means for every S pages, Jada reads 1.25S
Answer:
w = 3 is your answer.
Step-by-step explanation:
You want to get w by itself.
<em>(2w - 1)/(4) = 2 - w </em><u>You will add the w on both sides.</u>
<em>(3w - 1)/(4) = 2 </em><u>You will multiply 4 on both sides.</u>
<em>3w - 1 = 8 </em><u>You will add 1 on both sides.</u>
<em>3w = 9 </em><u>You will divide 3 on both sides.</u>
w = 3 is your answer.
Answer:
4.8m
Step-by-step explanation:
Answer:
512
Step-by-step explanation:
Suppose we ask how many subsets of {1,2,3,4,5} add up to a number ≥8. The crucial idea is that we partition the set into two parts; these two parts are called complements of each other. Obviously, the sum of the two parts must add up to 15. Exactly one of those parts is therefore ≥8. There must be at least one such part, because of the pigeonhole principle (specifically, two 7's are sufficient only to add up to 14). And if one part has sum ≥8, the other part—its complement—must have sum ≤15−8=7
.
For instance, if I divide the set into parts {1,2,4}
and {3,5}, the first part adds up to 7, and its complement adds up to 8
.
Once one makes that observation, the rest of the proof is straightforward. There are 25=32
different subsets of this set (including itself and the empty set). For each one, either its sum, or its complement's sum (but not both), must be ≥8. Since exactly half of the subsets have sum ≥8, the number of such subsets is 32/2, or 16.
Answer:
Step-by-step explanation:
You need to add $6.50 and $11.75 and you get $18.25.