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3 years ago

-8x + 2x PLEASE HELP ME

Mathematics

2 answers:

Lelu [443]3 years ago

6 0

Answer:

-6x

Step-by-step explanation:

when there is a negative and a positive we subtract them

in this equation -8x+2x there is a negative and a positive so we subtract them

and the number will be negative because 8 is bigger than 2.

-8x+2x =

-6x

BabaBlast [244]3 years ago

3 0

Answer: -6x

??? Is that the question just simplify it or something else

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Step-by-step explanation:

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3 years ago

When asked to find a number one-tenth as large as another number, what operation would you use? What about when asked to find a

kherson [118]

Apply division by 10 when one tenth of a number is required and apply multiplication by 10 when 10 times of a number is required.

<u>Solution:</u>

Need to determine what operation is required to get one-tenth of a number and 10 times of a number

To get one tenth of a number, divide the number by 10.

For example to get one – tenth of 100, divide it by 10, we get 10 as a result.

$\frac{1}{10} \times 100 = 10$

To get ten times of a number, multiply the number by 10

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Hence apply division by 10 when one tenth of a number is required and apply multiplication by 10 when 10 times of a number is required.

6 0

3 years ago

29.

Elis [28]

Answer:

Sum of their present ages = 20 years

Step-by-step explanation:

Present age :

Neha's age = x years

Reemas' age = x - 4

After 5 years:

Neha's age = (x +5) years

Reemas' age = (x - 4 + 5 ) = x + 1

Sum of the ages of Reema and Neha will be 30

Therefore,

x + 5 + x + 1 = 30

x + x + 5 + 1 = 30

2x + 6 = 30

2x = 30 - 6

2x = 24

x = 24/2

x = 12

Neha's age = 12 years

Reema's age = 12 - 4 = 8 years

Sum of their present ages = 12 + 8 = 20 years

4 0

3 years ago

Which side lengths form a right triangle?

STALIN [3.7K]

Answer:

8, 15, 17 and $\sqrt{2} , \sqrt{2}, 2$

Step-by-step explanation:

$c=\sqrt{a^2+b^2}$

$33=/=\sqrt{5^2+\sqrt{8}^2 }$

$17=\sqrt{8^2+15^2}$

$2=\sqrt{\sqrt{2}^2+\sqrt{2}^2 }$

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3 years ago

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Katyanochek1 [597]

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8 0

3 years ago