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hoa [83]
3 years ago
5

Which list is in order from least to greatest?  (PS you will see it is more organized once you click on the question)

Mathematics
1 answer:
Studentka2010 [4]3 years ago
4 0
I don't understand the way you put the answeres because 58 is the largest number here yet its before .78 on f and g on plus the number occurs 2 times
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What is the value of the letter n?
sleet_krkn [62]

Answer:

The value of n depends on the questin. N would be a variable in an equation.

Step-by-step explanation:

For example. 2*n=6

n is the variable in the equation. Therefore, the value of n is 3. Because 2*3=6.

8 0
3 years ago
I had 1/4 lasagna left i want to split that equally into 3 days how much would i eat each day?
Triss [41]
1/4 divided by 3
3/1 would become 1/3 because you changed from division to multiplication
1/4 times 1/3= 1/12
Hope this helped
6 0
3 years ago
Read 2 more answers
FIND THE SURFACE AREA HELP ASAP GET BRAINLISTS
3241004551 [841]

Answer:

\large\boxed{a.\ 7200\pi\ mm^2}

Step-by-step explanation:

The formula of a surface area of a cylinder:

S.A.=2\pi r(r+H)

r - radius

H - height

We have r = 40mm and H = 50mm. Substitute:

S.A.=2\pi(40)(40+50)=80\pi(90)=7200\pi\ mm^2

4 0
4 years ago
What is the positive slope of the asymptote of (y+11)^2/100-(x-6)^2/4=1? The positive slope of the asymptote is .
VladimirAG [237]

Answer:

the  positive slope of the asymptote = 5

Step-by-step explanation:

Given that:

\frac{(y+11)^2}{100} -\frac{(x-6)^2}{4} =1

Using the standard form of the equation:

\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}= 1

where:

(h,k) are the center of the hyperbola.

and the y term is in front of the x term  indicating that the  hyperbola opens up and down.

a = distance that indicates  how far above and below of the center the vertices of the hyperbola are.

For the above standard equation; the equation for the asymptote is:

y = \pm \frac{a}{b} (x-h)+k

where;

\frac{a}{b} is the slope

From above;

(h,k) = 11, 100

a^2 = 100

a = \sqrt{100}

a = 10

b^2 =4

b = \sqrt{4}

b = 2

y = \pm \frac{10}{2} (x-11)+2

y = \pm 5 (x-11)+2

y = 5x-53 , -5x -57

Since we are to find the positive slope of the asymptote: we have  

\frac{a}{b} to be  the slope in the equation  y = \pm \frac{10}{2} (y-11)+2

\frac{a}{b}  = \frac{10}{2}

\frac{a}{b}  = 5

Thus, the  positive slope of the asymptote = 5

8 0
3 years ago
Gabriela has an average daily balance of $232.94 on her credit card. Her card charges 9.25% annual interest. What will her month
allsm [11]

Answer:

Step-by-step explanation:

B

7 0
3 years ago
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