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3 years ago

Which list is in order from least to greatest? (PS you will see it is more organized once you click on the question)

1 answer:

Studentka2010 [4]3 years ago

4 0

I don't understand the way you put the answeres because 58 is the largest number here yet its before .78 on f and g on plus the number occurs 2 times

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What is the volume <br> 180<br> 360<br> 120<br> 720

kozerog [31]

Answer:

360

Step-by-step explanation:

5 0

3 years ago

Please help Ladder question!!

PIT_PIT [208]

Answer:

Step-by-step explanation:

This is a related rates problem from calculus using implicit differentiation. The main equation is going to be Pythagorean's Theorem and then the derivative of that. Pythagorean's Theorem is

$x^2+y^2=c^2$ where c is the hypotenuse and is a constant. Therefore, the derivative of this with respect to time, and using implicit differentiation is

$2x\frac{dx}{dt}+2y\frac{dy}{dt}=0$ and dividing everything by 2 to simplify a bit:

$x\frac{dx}{dt}+y\frac{dy}{dt}=0$ . Upon analyzing that equation, it looks like we need values for x, y, $\frac{dx}{dt}$ , and $\frac{dy}{dt}$ . And here's what we were given:

$\theta=45$ and $\frac{dx}{dt}=.5$ In the greater realm of things, that's nothing at all.

BUT we can use the right triangle and the angle we were given to find both x and y. The problem we are looking to solve is to

Find $\frac{dy}{dt}$ at the instant that $\frac{dx}{dt}$ = .5.

Solving for x and y:

$tan45=\frac{x}{6}$ and

6tan45 = x ( and since this is a 45-45-90 triangle, y = x):

$6(\frac{\sqrt{2} }{2})=x=y$ so

$x=y=3\sqrt{2}$ and now we can fill in our derivative. Remember the derivative was found to be

$x\frac{dx}{dt}+y\frac{dy}{dt}=0$ so

$3\sqrt{2}(\frac{1}{2})+3\sqrt{2}\frac{dy}{dt}=0$ and

$\frac{3\sqrt{2} }{2}+3\sqrt{2} \frac{dy}{dt}=0$ and

$3\sqrt{2}\frac{dy}{dt}=-\frac{3\sqrt{2} }{2}$ and multiplying by the reciprocal of the left gives us:

$\frac{dy}{dt}=-\frac{3\sqrt{2} }{2}(\frac{1}{3\sqrt{2} })$ so

$\frac{dy}{dt}=-\frac{1}{2}\frac{m}{s}$

8 0

3 years ago

Find the perimeter and area of the polygon shown below. The polygon is a trapezoid made up of a rectangle and a right triangle.

algol13

Since, the polygon is a trapezoid made up of a rectangle and a right triangle. Therefore, according to the question, the figure of the polygon is attached.

Since, perimeter is the total length of the outer boundary of the figure. Therefore,

Perimeter of the polygon is $=AB+BE+ED+DC+CA$