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hoa [83]
3 years ago
5

Which list is in order from least to greatest?  (PS you will see it is more organized once you click on the question)

Mathematics
1 answer:
Studentka2010 [4]3 years ago
4 0
I don't understand the way you put the answeres because 58 is the largest number here yet its before .78 on f and g on plus the number occurs 2 times
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In a valcano, erupting lava flows continuously through a tube system about 19 kilometers to the sea. assume a lava flow speed 0.
Sunny_sXe [5.5K]

Lava flows continuously about 19 kilometers to sea if speed of  lava is 0.5 kilometer per hour then it will take 38 hours to reach the sea.

As given,

Distance covered = 19kilometers

Speed of lava = 0.5 kilometer per hour

0.5 kilometers=1 hour

⇒ 1kilometers = (1/0.5)hour

⇒ 19 kilometers = (19 / 0.5) hour

⇒ 19 kilometers = 38 hours

Therefore, lava flows continuously about 19 kilometers to the sea if speed of the lava is 0.5 kilometer per hour then it will take 38 hours to reach the sea.

Learn more about speed here

brainly.com/question/28224010

#SPJ4

4 0
1 year ago
2 − 10n = 2 + 4n<br> What does n equal?
tiny-mole [99]

Answer:

0 =n

Step-by-step explanation:

2 − 10n = 2 + 4n

Add 10n to each side

2 − 10n+10n = 2 + 4n+ 10n

2 = 2 + 16n

Subtract 2 from each side

2-2 = 2+16n-2

0 = 16n

Divide each side by 16

0/16 = 16n/16

0 =n

8 0
3 years ago
Read 2 more answers
Perform the indicated operations. Write the answer in standard form, a+bi.<br> 5-3i / -2-9i
Vsevolod [243]

\huge \boxed{\mathfrak{Answer} \downarrow}

\large \bf\frac { 5 - 3 i } { - 2 - 9 i } \\

Multiply both numerator and denominator of \sf \frac{5-3i}{-2-9i} \\ by the complex conjugate of the denominator, -2+9i.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2-9i\right)\left(-2+9i\right)})  \\

Multiplication can be transformed into difference of squares using the rule: \sf\left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2\right)^{2}-9^{2}i^{2}})  \\

By definition, i² is -1. Calculate the denominator.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{85})  \\

Multiply complex numbers 5-3i and -2+9i in the same way as you multiply binomials.

\large \bf \: Re(\frac{5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9i^{2}}{85})  \\

Do the multiplications in \sf5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9\left(-1\right).

\large \bf \: Re(\frac{-10+45i+6i+27}{85})  \\

Combine the real and imaginary parts in -10+45i+6i+27.

\large \bf \: Re(\frac{-10+27+\left(45+6\right)i}{85})  \\

Do the additions in \sf-10+27+\left(45+6\right)i.

\large \bf Re(\frac{17+51i}{85})  \\

Divide 17+51i by 85 to get \sf\frac{1}{5}+\frac{3}{5}i \\.

\large \bf \: Re(\frac{1}{5}+\frac{3}{5}i)  \\

The real part of \sf \frac{1}{5}+\frac{3}{5}i \\ is \sf \frac{1}{5} \\.

\large  \boxed{\bf\frac{1}{5} = 0.2} \\

3 0
2 years ago
In Exploration 5.4.2 Question 2, what conclusion can you make about the value of the derivative at
givi [52]

The value of the derivative at the maximum or minimum for a continuous function must be zero.

<h3>What happens with the derivative at the maximum of minimum?</h3>

So, remember that the derivative at a given value gives the slope of a tangent line to the curve at that point.

Now, also remember that maximums or minimums are points where the behavior of the curve changes (it stops going up and starts going down or things like that).

If you draw the tangent line to these points, you will see that you end with horizontal lines. And the slope of a horizontal line is zero.

So we conclude that the value of the derivative at the maximum or minimum for a continuous function must be zero.

If you want to learn more about maximums and minimums, you can read:

brainly.com/question/24701109

4 0
2 years ago
53,806 in expanded form using exponents
Sholpan [36]
53.806= 5*10^5+3*10^4+8*10^3+6
4 0
3 years ago
Read 2 more answers
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