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vladimir2022 [97]
3 years ago
7

James ran 4 laps and walked 2 laps When running his average speed was 2.5 minutes per lap When walking his average speed was 4.9

minutes per lap How long did it take James to complete 6 laps? 7.4 minutes 9.9 minutes 14.8 minutes Or 19.8 minutes
Mathematics
1 answer:
lutik1710 [3]3 years ago
5 0

Answer:

19.8 minutes

Step-by-step explanation:

Total time the 4 laps was completed = 4 x 2.5 = 10 minutes

Total time the 2 laps was completed = 2 x 4.9 = 9.8 minutes

total time = 10 minutes + 9.8 minutes = 19.8 minutes

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Step-by-step explanation:

We need to create a ratio. so Aubree practices the piano for 1197 min: in 3 weeks. So for 1 week, we have to divide 1197 by 3, so 1197/=399. And so we know that 1 week is 7 days, just divide 399 by 7! 399/7=57. The rate that she practiced per day is 57 minutes. So one last final step just to check if this answer is correct is to divide 57 by 60, and that is 0.95. 0.95 out of 1.00 minutes per day is 95/100. Cross multiply with x/60, and you will get your answer, which is 57.

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1) Lithium isotope rations are important to medicine, the 6Li/7Li ratio in a standard reference material was measured several ti
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Answer:

1) 0.0826052-2.776\frac{0.000013424}{\sqrt{5}}=0.082588    

0.0826052+2.776\frac{0.000013424}{\sqrt{5}}=0.0826219    

b) ME= 2.776\frac{0.000013424}{\sqrt{5}}=0.0000166653

And we want 2/3 of the margin of error so then would be: 2/3 ME = 0.00001111

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (1)

And on this case we have that ME =0.00001111016 and we are interested in order to find the value of n, if we solve n from equation (1) we got:

n=(\frac{z_{\alpha/2} s}{ME})^2   (2)

Replacing we got:

n=(\frac{2.776(0.000013424)}{0.00001111})^2 =11.25 \approx 12

So the answer for this case would be n=12 rounded up to the nearest integer

Step-by-step explanation:

Information given

0.082601, 0.082621, 0.082589, 0.082617, 0.082598

We can calculate the sample mean and deviation with the following formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X=0.0826052 represent the sample mean

\mu population mean

s=0.000013424 represent the sample standard deviation

n=5 represent the sample size  

Part 1

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom, given by:

df=n-1=5-1=4

The Confidence level is 0.95 or 95%, and the significance would be \alpha=0.05 and \alpha/2 =0.025, the critical value would be using the t distribution with 4 degrees of freedom: t_{\alpha/2}=2.776

Now we have everything in order to replace into formula (1):

0.0826052-2.776\frac{0.000013424}{\sqrt{5}}=0.082588    

0.0826052+2.776\frac{0.000013424}{\sqrt{5}}=0.0826219    

Part 2

The original margin of error is given by:

ME= 2.776\frac{0.000013424}{\sqrt{5}}=0.0000166653

And we want 2/3 of the margin of error so then would be: 2/3 ME = 0.00001111

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (1)

And on this case we have that ME =0.00001111016 and we are interested in order to find the value of n, if we solve n from equation (1) we got:

n=(\frac{z_{\alpha/2} s}{ME})^2   (2)

Replacing we got:

n=(\frac{2.776(0.000013424)}{0.00001111})^2 =11.25 \approx 12

So the answer for this case would be n=12 rounded up to the nearest integer

3 0
3 years ago
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