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3 years ago

Pls help asap...urgently help needed!!!tia

Mathematics

1 answer:

ziro4ka [17]3 years ago

3 0

Answer:

(a) v = 1536640/ m^2.

(b) (i) 1186 m/s.

(ii) 52.4g .

Step-by-step explanation:

(a) The equation is v = k / m^2 where k is the constant of variation.

When m = 49, v = 640 so 640 = k / 49^2

k = 640 * 49^2

= 1,536,640.

Therefore the relation is v = 1536640/ m^2.

(b) (i)

When m = 36g, the speed v = 1536640 / 36^2

= 1186 m/s.

(ii) When the speed is 560 m/s :-

560 = 1536640 / m^2

m^2 = 1536640 / 560

= 2744

mass m = √2744

= 52.4g

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Viefleur [7K]

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2 years ago

I need to know if there functions or not (algebra)

faust18 [17]

Answer:

Number 14 is a function and Number 16 is NOT a function.

Step-by-step explanation:

To check if a set of numbers form a function, you can look at the x values or the imput values.

For number 14 the x values are : 4,-3,-4,5,6. When looking at these values, there can only be one of each number.

For example in number 16, there's two 0's and we cannot allow that! So therefore, number 16 is not a function.

Also note, the y values are called the outputs.

A function is only allowed to have ONE imput with each output.

Hope this helps! :)

4 0

3 years ago

Every day, a comes to the bus stop at the same time, and boards the first bus that arrives. the arrival of the first bus is an e

mylen [45]

So the waiting time for a bus has density f(t)=λe−λtf(t)=λe−λt, where λλ is the rate. To understand the rate, you know that f(t)dtf(t)dt is a probability, so λλ has units of 1/[t]1/[t]. Thus if your bus arrives rr times per hour, the rate would be λ=rλ=r. Since the expectation of an exponential distribution is 1/λ1/λ, the higher your rate, the quicker you'll see a bus, which makes sense.

So define X=min(B1,B2)X=min(B1,B2), where B1B1 is exponential with rate 33 and B2B2 has rate 44. It's easy to show the minimum of two independent exponentials is another exponential with rate λ1+λ2λ1+λ2. So you want:

P(X>20 minutes)=P(X>1/3)=1−F(1/3),P(X>20 minutes)=P(X>1/3)=1−F(1/3),

where F(t)=1−e−t(λ1+λ2)F(t)=1−e−t(λ1+λ2).

8 0

3 years ago

Alondra received a 14% hourly raise, but the number of hours worked decreased by 7.5%. If her wage was $10.50 an hour and she wo

Elodia [21]

Answer:

She will earn $442.89 in one week after the changes.

And this is more than her previous weekly earnings.

Step-by-step explanation:

Given:

Alondra received a 14% hourly raise, but the number of hours worked decreased by 7.5%. If her wage was $10.50 an hour and she worked 40 hours per week before the changes.

Now, to find money she will earn in one week after the changes.

Her wage was = $10.50.

She worked per week = 40 hours.

So, her salary before changes:

$10.50\times 40\\\\=\$420.$

Thus, the salary per week before changes is $420.

Now, to get her salary after 14% hourly raise:

$10.50+14\%\ of\ 10.50\\\\=10.50+\frac{14}{100} \times 10.50\\\\=10.50+1.47\\\\=11.97$

Salary after hourly raise = $11.97 per hour.

Then, to get the number of hours worked decreased by 7.5%:

$40-7.5\%\ of\ 40\\\\=40-\frac{7.5}{100} \times 40\\\\=40-3\\\\=37.$

Number of hours per week after hours of worked decreased = 37 hours.

Now, to get the salary after changes:

Salary after hourly raise × number of hours per week after hours of worked decreased

$=11.97\times 37$

$=\$442.89.$

Salary after changes in one week = $442.89.

As, the previous salary was $420 in one week. 

And after changes this salary is $442.89 in one week which is more than previous. 

Therefore, she will earn $442.89 in one week after the changes.

And this is more than her previous weekly earnings.

4 0

3 years ago

Lara makes 2 cakes in 3/4 mins. If she do 4 cakes then how many min did she take to do?

Julli [10]

She took 1 1/2 minutes to make 4 cakes. You can multiply 3/4 by 2. You get 6/4 = 1 2/4 = 1 1/2. You can also add 3/4 + 3/4. That is 6/4 = 1 2/4 = 1 1/2.
Hope it helped.

6 0

3 years ago