20 lbs $17.20<br> Which is the better buy? Explain using ratios<br> 30 lb om $25.20

Find 80 percent of 25

Elden [556K]

Use 80% *25 than you can get 20.

3 0

3 years ago

PLEASE HELP THIS IS VERY IMPORTANT I WILL GIVE YOU BRAIN THING IF ITS CORRECT (you can use a calculator if you want)

saul85 [17]

Answer:

Step-by-step explanation: if there are 500 pieces of paper and the entire stack is 1.875 inches tall, you devide the total height by 500. I know Deigo is wrong because you can easily reverse check his work by multiplying 0.015 by the total number of papers 500 you will get 7.5 which is not the height of the stack

1.875/500=0.00375

each piece of paper is 0.00375

8 0

3 years ago

Orlando invests $1000 at 6% annual interest compounded daily and Bernadette invests $1000 at 7%

Montano1993 [528]

Answer:

6 Years

Step-by-step explanation:

Orlando invests $1000 at 6% annual interest compounded daily.

Orlando's investment = $A=1000(1+\frac{0.06}{365})^{(365\times t)}$

Bernadette invests $1000 at 7% simple interest.

Bernadette's investment = A = 1000(1+0.07×t)

By trail and error method we will use t = 5

Bernadette's investment will be after 5 years

1000(1 + 0.07 × 5)

= 1000(1 + 0.35)

= 1000 × 1.35

= $1350

Orlando's investment after 5 years

$A=1000(1+\frac{0.06}{365})^{(365\times 5)}$

= $1000(1+0.000164)^{1825}$

= $1000(1.000164)^{1825}$

= 1000(1.349826)

= 1349.825527 ≈ $1349.83

After 5 years Orlando's investment will not be more than Bernadette's.

Therefore, when we use t = 6

After 6 years Orlando's investment will be = $1433.29

and Bernadette's investment will be = $1420

So, after 6 whole years Orlando's investment will be worth more than Bernadette's investment.

8 0

3 years ago

The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra

Snezhnost [94]

Let $X$ denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by $X_1,\ldots,X_{36}$ , each independently and identically distributed with distribution $X_i\sim\mathcal N(26,7.2)$ .

You want to find

$\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)$

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

$\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)$

Recall that if $X\sim\mathcal N(\mu,\sigma)$ , then the sampling distribution $\overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right)$ with $n$ being the size of the sample.

Transforming to the standard normal distribution, you have

$Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}$

so that in this case,

$Z=6\dfrac{\overline X-26}{7.2}$

and the probability is equivalent to

$\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)$
$=\mathbb P(Z>1.481)\approx0.0693$

5 0

3 years ago

Help on this question!!!!!!

Lilit [14]

Answer:

13

Step-by-step explanation:

use the Pythagorean theorem; five squared plus twelve squared is equal to the missing side squared, 25+144=169, the sqrt of 169 is 13

8 0

3 years ago

20 lbs $17.20 Which is the better buy? Explain using ratios 30 lb om $25.20