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MatroZZZ [7]
3 years ago
13

I NEED HELP :( WILL MARK BRAINLIEST!! NEED HELP ASAP

Mathematics
1 answer:
Elden [556K]3 years ago
6 0

Answer:

the answer is B

Step-by-step explanation:

The lowest point for Y is -1 therefore that's the first number and the highest point is 1 therefore thats the last number so naturally the range is -1≤Y≤1

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Select all radical expressions that are equivalent to 347. (3√4)7 (3√7)4 21−−√4 37−−√4 81−−√7 12−−√7
vichka [17]

Answer:

can you add the answer choices please? thank you!

Step-by-step explanation:

4 0
3 years ago
Please help ASAP. The question is down below. Thanks
beks73 [17]

Answer:

B

Step-by-step explanation:

there is three sections to be fenced using 78 m of fence so it would be letter B.

6 0
3 years ago
Simplify: 5 + p > 3 please help
Readme [11.4K]

Answer:

p > -2

Step-by-step explanation:

5 + p > 3

p > 3 -5

p > -2

7 0
3 years ago
Grace invested $5,200 in an account paying an interest rate of 4.6% compounded daily. Assuming no deposits or withdrawals are ma
nlexa [21]

Answer:

Step-by-step explanation:

Use this formula for when compounding is either not continuous or is not annually:

A(t)=P(1+\frac{r}{n})^{(n)(t)} where P is the initial investment, r is the interest rate in decimal form, n is the number of times the compounding occurs per year, and t is the time in years.  For us:

P = 5200,

r = .046,

n = 365, and

t = 11

A(t)=5200(1+\frac{.046}{365})^{(365)(11)} and

A(t)=5200(1+.000126)^{4015} and

A(t)=5200(1.000126)^{4015} and

A(t) = 5200(1.658408042) so

A(t) = $8623.72

8 0
3 years ago
A highway engineer knows that his crew can lay 5 miles of highway on a clear day, 2 miles on a rainy day, and only 1 mile on a s
lesya692 [45]

Answer:

Mean = 3.7

Variance = 2.61

Step-by-step explanation:

From the data given; we can represent our table into table format for easier solution and better understanding.

Given that:

A highway engineer knows that his crew can lay 5 miles of highway on a clear day, 2 miles on a rainy day, and only 1 mile on a snowy day

Let X represent the crew;

P(X) represent their respective probabilities

                   clear  day           rainy day            snowy day

X                  5                          2                           1

P(X)              0.6                       0.3                       0.1

From Above; we can determine our X*P(X) and X²P(X)

Let have the two additional columns to table ; we have

X                      P(X)                      X*P(X)                       X²P(X)

5                        0.6                          3                               15

2                        0.3                        0.6                             1.2

1                         0.1                          0.1                            0.1

Total                  1.0                        3.7                             16.3

The mean \mu can be calculated by using the formula:

\sum \limits ^n _{i=1}X_i P(X_i)

Therefore ; mean \mu = 3.7

Variance \sigma^2 = \sum \limits ^n _{i=1}X^2_i P(X_i)- \mu^2

Variance = 16.3 -3.7²

Variance = 16.3 - 13.69

Variance = 2.61

4 0
4 years ago
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