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MatroZZZ [7]
3 years ago
13

I NEED HELP :( WILL MARK BRAINLIEST!! NEED HELP ASAP

Mathematics
1 answer:
Elden [556K]3 years ago
6 0

Answer:

the answer is B

Step-by-step explanation:

The lowest point for Y is -1 therefore that's the first number and the highest point is 1 therefore thats the last number so naturally the range is -1≤Y≤1

You might be interested in
The lifetime of a certain type of battery has a mean value 20 hours and standard deviation 3 hours. A bulk package of these batt
vodka [1.7K]

Answer:

The distribution of average life time is approximately normallyl distributed with mean 20 hours and standard deviation of 0.4743 hours

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem

\mu = 20, \sigma = 3, n = 40, s = \frac{3}{\sqrt{40}} = 0.4743

The distribution of average life time is approximately normallyl distributed with mean 20 hours and standard deviation of 0.4743 hours

8 0
4 years ago
00:00
Furkat [3]

Answer:

-2

Step-by-step explanation:

Subtracting a negative number is the same as adding it, so this is basically just negative 8 plus 6, which is -2. Don't know who was right though, you kinda left that part of the question out.

5 0
4 years ago
Please help, thank you
denpristay [2]

Answer:

licensed drivers who makes calls while driving

Step-by-step explanation:

8 0
3 years ago
A marketing research company desires to know the mean consumption of milk per week among males over age 32. A sample of 710 male
nydimaria [60]

Answer:

(4.5, 4.7)

Step-by-step explanation:

Hi!

Lets call X to the consumption of milk per week among males over age 32. X has a normal distribution with mean μ and standard deviation σ.

X \sim N(\mu, \sigma)

When you know the population standard deviation σ of X  ,  and the sample mean is \hat X, the  variable q has distribution N(0,1):

q = \frac{\hat X - \mu}{\sigma} \sim N(0,1)

Then you have:

P(-k < q

This defines a C - level confidence interval. For each C the value of k is well known. In this case C = 0.98, then k = 2.326

Then the confidence interval is:

(4.6 - 2.326*\frac{0.8}{\sqrt{710}}, 4.6 + 2.326*\frac{0.8}{\sqrt{710}})\\ (4.5, 4.7)

5 0
4 years ago
If a restaurant charges $9.90 for 2 sandwiches, how much will the restaurant charge for 15 sandwiches?
natulia [17]
They will charge 74.25
6 0
3 years ago
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