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3 years ago

3+1905=x . .......................

Mathematics

1 answer:

Alex_Xolod [135]3 years ago

4 0

<h2>Answer:</h2><h2>x = 1908</h2><h2></h2><h2>Hope this helps!!</h2>

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Consider the diagram below.<br> Which of the following statements is correct?

Nutka1998 [239]

Answer:

Step-by-step explanation:

The diagram shows two parallel lines XY and WV.

1. Parallel lines XY and WV are cut by transversal XW, then angles YXZ and VWZ are congruent as alternate interior angles.

2. Parallel lines XY and WV are cut by transversal YV, then angles XYZ and WVZ are congruent as alternate interior angles.

AA similarity theorem states if two angles of one triangle are congruent to two angles of another triangle, then the triangles are similar.

So, $\triangle XYZ\sim \triangle WVZ$ by AA similarity

7 0

4 years ago

Read 2 more answers

Can anybody help me please hurry this is due

larisa [96]

Answer:

1. 3 7/12 (decimal: 3.583333)

2. -5 3/28

3. 2 29/40

4. −1 9 /14

7 0

3 years ago

7m + 3mn<br> when m = 3 and n = -4

nadya68 [22]

Answer:

-15

Step-by-step explanation:

When m=3 and n=-4

So, put the values

7(3)+3(3)(-4)

-> -15

4 0

3 years ago

Read 2 more answers

Consider three boxes with numbered balls in them. Box A con- tains six balls numbered 1, . . . , 6. Box B contains twelve balls

murzikaleks [220]

Answer:

a) 0.73684

b) 2/3

Step-by-step explanation:

part a)

$P ( A is 1 / exactly two balls are 1) = \frac{P ( A is 1 and that exactly two balls are 1)}{P (Exactly two balls are one)}$

Using conditional probability as above:

(A,B,C)

Cases for numerator when:

P( A is 1 and exactly two balls are 1) = P( 1, not 1, 1) + P(1, 1, not 1)

= $(\frac{1}{6}* \frac{11}{12}*\frac{1}{4}) + (\frac{1}{6}*\frac{1}{12}*\frac{3}{4}) = 0.048611111$

Cases for denominator when:

P( Exactly two balls are 1) = P( 1, not 1, 1) + P(1, 1, not 1) + P(not 1, 1 , 1)

$= (\frac{1}{6}* \frac{11}{12}*\frac{1}{4}) + (\frac{1}{6}*\frac{1}{12}*\frac{3}{4}) + (\frac{5}{6}*\frac{1}{12}*\frac{1}{4})= 0.0659722222$

Hence,

$P ( A is 1 / exactly two balls are 1) = \frac{P ( A is 1 and that exactly two balls are 1)}{P (Exactly two balls are one)} = \frac{0.048611111}{0.06597222} \\\\= 0.73684$

Part b

$P ( B = 12 / A+B+C = 21) = \frac{P ( B = 12 and A+B+C = 21)}{P (A+B+C = 21)}$

Cases for denominator when:

P ( A + B + C = 21) = P(5,12,4) + P(6,11,4) + P(6,12,3)

$= 3*P(5,12,4 ) =3* \frac{1}{6}*\frac{1}{12}*\frac{1}{4}\\\\= \frac{1}{96}$

Cases for numerator when:

P (B = 12 & A + B + C = 21) = P(5,12,4) + P(6,12,3)

$= 2*P(5,12,4 ) =2* \frac{1}{6}*\frac{1}{12}*\frac{1}{4}\\\\= \frac{1}{144}$

Hence,

$P ( B = 12 / A+B+C = 21) = \frac{\frac{1}{144} }{\frac{1}{96} }\\\\= \frac{2}{3}$

4 0

3 years ago

What is the area of this figure?

Elanso [62]

First of all we can draw a parallel line to divide the figure into a triangle and a rectangle as shown in the figure. To find the area of our rectangle, remember that the area of a rectangle is length times width, so $A_{r} =lw$ . Since we know for our figure that the length and width of our rectangle are 13cm and 6cm respectively, lets replace those values in our formula to get its area:
$A _{r} =(13cm)(6cm)$
$A=78cm^{2}$
Similarly, the area of a triangle is one half times base times height, so $At=( \frac{1}{2})bh$ . Since we know that our base is 8cm and our height 6cm, lets replace those values in our equation to find the area of our triangle:
$A_{t} =( \frac{1}{2})(8cm)(6cm)$
$A_{t} =24cm^{2}$

Now the only thing left is add our areas:
$A_{total} =78cm^{2}+24cm^{2} =102cm^{2}$

We can conclude that the correct answer is <span>A. 102</span>

4 0

3 years ago