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2 years ago

3+1905=x . .......................

Mathematics

1 answer:

Alex_Xolod [135]2 years ago

4 0

<h2>Answer:</h2><h2>x = 1908</h2><h2></h2><h2>Hope this helps!!</h2>

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Helppp me the awnser is in the picture

Sindrei [870]

Y = 5x + 3 please mark me brainliest and comment if you want an explanation.

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3 years ago

Can you make a triangle?<br> 8, 2,8

pychu [463]

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Step-by-step explanation:

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3 years ago

When muiltplying two exponents, If the base numbers are DIFFERENT can u add the two exponents?

aleksley [76]

Multiplying exponents with different bases
First, multiply the bases together. Then, add the exponent. Instead of adding the two exponents together, keep it the same.

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3 years ago

Which of the following functions are solutions of the differential equation y'' + y = 3 sin x? (select all that apply)

DiKsa [7]

Answer:

Step-by-step explanation:

We must compute the derivatives and check if the equation is satisfied.

A. $y'=(3\sin x)'=3\cos x$ . Differentiate again to get $y''=(3\cos x)'=-3\sin x$ , then $y''+y=-3\sin x+3\sin x=0\neq 3\sin x$ so this choice of y doesn't solve the equation.

B. $y'=3\sin x+3x\cos x-5\cosx +5x\sin x=(5x+3)\sin x+(3x-5)\cos x$ and $y''=5\sin x+(5x+3)\cos x+3\cos x-(3x-5)\sin x=(10-3x)\sin x+(5x+6)\cos x$ , then $y''+y=10\sin x+6\cos x\neq 3\sin x$ so y is not a solution

C. $y'=\frac{-3}{2}\cos x+\frac{3}{2}x\sin x$ hence $y''=\frac{3}{2}\sin x+\frac{3}{2}\sin x+\frac{3}{2}x\cos x=3\sin x+\frac{3}{2}x\cos x$ . Then $y''+y=3\sin x+\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\sin x$ so y is a solution.

D. $y'=-3\sin x$ and $y''=-3\cos x$ , then $y''+y=0$ thus y isn't a solution

E. $y'=\frac{3}{2}\sin x+\frac{3}{2}x\cos x$ hence $y''=\frac{3}{2}\cos x+\frac{3}{2}\cos x-\frac{3}{2}x\sin x=3\cos x-\frac{3}{2}x\cos x$ . Then $y''+y=3\cos x-\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\cos x\neq 3\sin x$ then y is not a solution.

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3 years ago

X+8=-15 help again sorryyy

suter [353]

X by its self is always 1x

1x+8=-15 you have to get rid of 8 by subtracting on both sides

1x=-23 now get rid of 1 by dividing on both sides

x=-23

8 0

3 years ago