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adoni [48]
3 years ago
14

Which triangles are congruent by AAS? Fill in the blank beside the triangles with yes or no.

Mathematics
2 answers:
Igoryamba3 years ago
8 0

Answer:

 

Step-by-step explanation:

o-na [289]3 years ago
3 0

Answer:

IM BOUT TO SOLVE

Step-by-step explanation:

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Please help with my geometry
erma4kov [3.2K]
25 = hypothenuse
14 = opposite
Use SOHCAHTOA
Give O and H, you can use sin
Sin^-1 = 14/25 = 34.0557
Round to hundreds
Solution: 34.06
8 0
3 years ago
Jamiah bought two 125 ounce bags of flour for baking. He used up 32 ounces of flour to bake a batch of brownies. How much flour
V125BC [204]

Answer: its 218

Step-by-step explanation: you just have to subtract 250 minus 32

7 0
2 years ago
15/16 divided by 20<br> 7/15 divided by 14
olga2289 [7]

Answer:

The first is 0.046 and the second is 0.033

Step-by-step explanation:

4 0
4 years ago
Can someone please help me with this?
melamori03 [73]

Answer: \Large\boxed{f(-9)=-189}

Step-by-step explanation:

f(x) = -3x² - 6x

<u>Requirements of the question</u>

Find the value of f(-9)

<u>Substitute values into the given function</u>

f(x) = -3x² - 6x

f(9) = -3 (-9)² - 6 (-9)

<u>Simplify the exponent</u>

f(9) = -3 (81) - 6 (-9)

<u>Simplify by multiplication</u>

f(-9) = (-243) - (-54)

<u>Simplify by subtraction</u>

\Large\boxed{f(-9)=-189}

Hope this helps!! :)

Please let me know if you have any questions

4 0
2 years ago
Find the exact values of the remaining five trigonometric functions of theta, suppose theta is an angle in the standard position
nexus9112 [7]

Answer:

\sin(\theta)=60/61\text{ and } \csc(\theta)=61/60\\\cos(\theta)=11/61\text{ and } \sec(\theta)=61/11\\\tan(\theta)=60/11\text{ and } \cot(\theta)=11/60

Step-by-step explanation:

So, we know that:

\tan(\theta)=60/11\text{ and } 90\textdegree

Since θ is in QI, this means that <em>all</em> of our trig ratios will be positive. Recall All Students Take Calculus. Since it's QI, we refer to A in All. The A tells us that all the ratios will be positive.

Now, let's figure out the remaining ratios knowing that all of them is positive. First, let's find the hypotenuse. Recall that tangent is the ratio of the <em>opposite side to the adjacent side</em>. So, we can use the Pythagorean Theorem to find the hypotenuse. So:

a^2+b^2=c^2

Substitute 60 for a and 11 for b:

60^2+11^2=c^2

Solve for c. Square both numbers:

3600+121=c^2

Add:

c^2=3721

Take the square root of both sides:

c=61

Therefore, the hypotenuse is 61.

So, our side lengths are: Opposite=60; Adjacent=11; and Hypotenuse=61.

Now that we know the lengths, we can find the other trig ratios:

Sine and Cosecant:

\sin(\theta)=opp/hyp

Substitute 60 for Opp and 61 for Hyp:

\sin(\theta)=60/61

Cosecant is the reciprocal of sine. So:

\csc(\theta)=61/60

Cosine and Secant:

\cos(\theta)=adj/hyp

Substitute 11 for Adj and 61 for Hyp:

\cos(\theta)=11/61

Secant is the reciprocal of cosine. So:

\sec(\theta)=61/11

Tangent and Cotangent:

We are already given that tangent is:

\tan(\theta)=60/11

Cotangent is the reciprocal of tangent. So:

\cot(\theta)=11/60

4 0
4 years ago
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