1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
e-lub [12.9K]
3 years ago
14

3. Fill the blanks to make the equivalent ratios. :9 = 10: 45 a. b. : 3 = 3:9​

Mathematics
1 answer:
professor190 [17]3 years ago
7 0

Answer:

:/

Step-by-step explanation:

You might be interested in
A mail order company charges 4.5% for shipping and handling. If the total order is 54.34 how much was the order total before shi
Andrews [41]

Answer:

$52

Step-by-step explanation:

Given that :

Amount charged for shipping and handling = 4.5%

Let cost of order = x

Total amount charged = 54.34

However,

total. Amount charged = (total cost + handling and shipping)

54.34 = x + 0.045x

54.34 = 1.045x

Order total before shipping = 54.34 / 1.045

Order total before shipping = 52

6 0
3 years ago
A large but sparsely populated county has two small hospitals, one at the south end of the county and one at the north end. The
Readme [11.4K]

Answer:

Step-by-step explanation:

Probability distribution of this type is a vicariate distribution because it specifies two random variable X and Y. We represent the probability X takes x and Y takes y by

f(x,y) = P((X=x,Y=y) ,

and given that the random variables are independent the joint pmf isbgiven by:

f(x,y) = fX(x) .fY(y) and this gives the table (see attachment)

(b) the required probability is given by considering X=0,1 and Y =0,1

f(x,y) = sum{(P(X ≤ 1, Y ≤ 1) }

= [0.1 +0.2 ] × [0.1 + 0.3]

= 0.3 × 0.4

= 0.12

Now we find

fX(x) = sum{[f(x.y)]} for y =0, 1 and similarly for fY(y)= sum{[f(x,y)]} for x=0, 1

fX(x) = sum{[f(x,y)]}= 0.1+0.3

= 0.4

fY(y) = sum{[f(x.y)]} = 0.1 + 0.2

= 0.3

Since fY(y) × fX(x) = 0.4 × 0.3

= 0.12

Hence f(x,y) = fX(x) .fY(y), the events are independent

(c) the required event is give by: [P(X<=1, PY<=1)]

= P(X<=1) . P(Y<=1)

= [sum{[f(x.y]} over Y=0,1] × [sum{[f(x.y)]}, over X= 0, 1

= 0.4 × 0.3

= 0.12

(d) the required event is given by the idea that: either The South has no bed and the North has or the the North has no bed and the South has. Let this event be A

A =sum[(P(X = 1<= x<= 4, Y =0)] + sum[P(X =0 Y= 1 <= x <= 3)]

A = [0.02 + 0.03 + 0.02 + 0.02] + [0.03 + 0.04 + 0.02]

A = [0.09] + [ 0.09]

A = 0.18

Pls note the sum of the vertical column X=2 is 0.3

3 0
4 years ago
Please help me @marcthetutor please if you cpuld help me as welll anybody please help wuth thorough explaining will mark as brai
Hunter-Best [27]

Answer:

w=3

Step-by-step explanation:

(w+3)x2=4w

2w+6=4w

2w+6-6=4w-6

2w-4w=4w-6-4w

-2w=-6

-2w/2 = -6/2

w=3

7 0
4 years ago
Can some one help me factor 6x^2+4x-10
Fudgin [204]
2(3x + 5) (x - 1)

This is done through factoring 2 out of the equation first...

2(3x^2 + 2x -5)

And then cross multiplying it
3 0
3 years ago
Evaluate the following integral using trigonometric substitution
serg [7]

Answer:

The result of the integral is:

\arcsin{(\frac{x}{3})} + C

Step-by-step explanation:

We are given the following integral:

\int \frac{dx}{\sqrt{9-x^2}}

Trigonometric substitution:

We have the term in the following format: a^2 - x^2, in which a = 3.

In this case, the substitution is given by:

x = a\sin{\theta}

So

dx = a\cos{\theta}d\theta

In this question:

a = 3

x = 3\sin{\theta}

dx = 3\cos{\theta}d\theta

So

\int \frac{3\cos{\theta}d\theta}{\sqrt{9-(3\sin{\theta})^2}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9 - 9\sin^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{\theta})}}

We have the following trigonometric identity:

\sin^{2}{\theta} + \cos^{2}{\theta} = 1

So

1 - \sin^{2}{\theta} = \cos^{2}{\theta}

Replacing into the integral:

\int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{2}{\theta})}} = \int{\frac{3\cos{\theta}d\theta}{\sqrt{9\cos^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{3\cos{\theta}} = \int d\theta = \theta + C

Coming back to x:

We have that:

x = 3\sin{\theta}

So

\sin{\theta} = \frac{x}{3}

Applying the arcsine(inverse sine) function to both sides, we get that:

\theta = \arcsin{(\frac{x}{3})}

The result of the integral is:

\arcsin{(\frac{x}{3})} + C

8 0
3 years ago
Other questions:
  • Figure TUVW ≌ figure ABCD, UV = 9, WT = 17, and TU = 13.
    12·2 answers
  • Evaluate 6x - y if x=5 and y=8
    8·2 answers
  • HELP ASAP!!!!Which function BEST expresses the linear relationship displayed by the scatter plot?
    8·2 answers
  • 17. What is the solution to -7s=-35? (1 point)<br> Os=-6<br> Os=-5<br> Os = 5<br> Os=6
    9·2 answers
  • I need help whats 9+10??? Please it an emergency and what y’all’s discord with number please!!!
    10·2 answers
  • Surface Area is [sa1] of the figure.
    12·2 answers
  • What is the point called where 2 lines intersect or cross? It is the ___________ to the system of equations
    15·2 answers
  • A cell phone company dropped the
    9·1 answer
  • Yahto needs 3 3/4 cups of sugar to make cookies. He needs an additional 3/4 cup for bread. Find the total amount.
    8·1 answer
  • HELPP I GIVE BRAINLESTT RN I NEED THIS IN 5 MINUTESSS RNNNN
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!