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2 years ago

One endpoint (-1,-5) Midpoint (2,3)

Mathematics

1 answer:

Alecsey [184]2 years ago

4 0

I don’t know the answer but I need a answer to this

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2/3 + 1/2 in simple form fractions

nata0808 [166]

Try and find the common denominator which is 6 since 2×3 is 6 then once u get ur denominator u have to find the numerator which would be 4/6+3/6 And that would equal 7/6 and if you would u would keep it like that but if u would have to change it into a mixed fraction it would be 1 and 1/6

Hoped this helped

3 0

2 years ago

Galina had two boxes with pieces of paper in each. In the first box, each piece of paper had one possible outcome from flipping

Natali5045456 [20]

Answer:

Step-by-step explanation:

3 0

3 years ago

The model represents an inequality. what is the solution set for the inequality?

Ierofanga [76]

Answer:

X > (greater than or equal to) -7

Step-by-step explanation:

3x + 15 > -6

3x > -21 (subtract 15 from both sides)

X > -7 (divide both sides by 3)

5 0

2 years ago

Find the surface area of x^2+y^2+z^2=9 that lies above the cone z= sqrt(x^@+y^2)

Mashcka [7]

The cone equation gives

$z=\sqrt{x^2+y^2}\implies z^2=x^2+y^2$

which means that the intersection of the cone and sphere occurs at

$x^2+y^2+(x^2+y^2)=9\implies x^2+y^2=\dfrac92$

i.e. along the vertical cylinder of radius $\dfrac3{\sqrt2}$ when $z=\dfrac3{\sqrt2}$ .

We can parameterize the spherical cap in spherical coordinates by

$\mathbf r(\theta,\varphi)=\langle3\cos\theta\sin\varphi,3\sin\theta\sin\varphi,3\cos\varphi\right\rangle$

where $0\le\theta\le2\pi$ and $0\le\varphi\le\dfrac\pi4$ , which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is $\dfrac3{\sqrt2}$ . So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

$\varphi=\cos^{-1}\left(\dfrac{\frac3{\sqrt2}}3\right)=\cos^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4$

Now the surface area of the cap is given by the surface integral,

$\displaystyle\iint_{\text{cap}}\mathrm dS=\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dv\,\mathrm du$
$=\displaystyle\int_{u=0}^{u=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}9\sin v\,\mathrm dv\,\mathrm du$
$=-18\pi\cos v\bigg|_{v=0}^{v=\pi/4}$
$=18\pi\left(1-\dfrac1{\sqrt2}\right)$
$=9(2-\sqrt2)\pi$

3 0

2 years ago

I NEED HELP!!<br>answer from the image below <br><br>m∠BCD =

nevsk [136]

Answer:

28 degrees

Step-by-step explanation:

If two parallel lines are cut by a transversal, then the pairs of corresponding angles are congruent.The corresponding angles are the ones at the same location at each intersection.

In the figure ABD and EDF are corresponding angles. So they are equal

So equation the angle ABD and EDF , we get

(3x+4) = (7x-20)

Group the like terms,

3x-7x = -20-4

-4x = -24

$x = \frac{-24}{-4}$

x = 6

Thus BCD will be,

(6x - 8)

=>(6(6)-8)

=>(36-8)

=> 28 degrees

4 0

2 years ago