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3 years ago

Which equation represents an inverse variation? O y = 2x Oy- O yo X O y = -5x

Mathematics

1 answer:

olga nikolaevna [1]3 years ago

6 0

O y = 2x is the answer

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Simplify the fraction and state the excluded value(s).

stira [4]

Answer:

$\displaystyle \frac{7x^2 + 4x - 20}{5x + 10} = \frac{7x - 10}{5}, x \neq -2$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Algebra I</u>

Terms/Coefficients

Factoring

<u>Calculus</u>

Discontinuities

Removable (Holes)
Jump (Piece-wise functions)
Infinite (Asymptotes)

Step-by-step explanation:

<u>Step 1: Define</u>

<u /> $\displaystyle \frac{7x^2 + 4x - 20}{5x + 10}$ <u />

<u />

<u>Step 2: Simplify</u>

[Frac - Numerator] Factor quadratic: $\displaystyle \frac{(7x - 10)(x + 2)}{5x + 10}$
[Frac - Denominator] Factor GCF: $\displaystyle \frac{(7x - 10)(x + 2)}{5(x + 2)}$
[Frac] Divide/Simplify: $\displaystyle \frac{(7x - 10)}{5}, x \neq -2$

When we divide (x + 2), we would have a <em>removable</em> <em>discontinuity</em>. If we were to graph the original function, we would see at x = -2 there would be a hole in the graph.

8 0

3 years ago

Enter a recursive rule for the geometric sequence.<br><br> 2,−6,18,−54,...

Luden [163]

Answer:

$a_n=-3a_{n-1}$ where $a_1=2$

Step-by-step explanation:

Recursive means you want to define a sequence in terms of other terms of your sequence.

The common ratio is what term divided by previous term equals.

The common ratio here is -6/2=18/-6=-54/18=-3.

Or in terms of the nth and previous term we could say:

$\frac{a_n}{a_{n-1}}=r$

where r is -3

$\frac{a_n}{a_{n-1}}=-3$

Multiply both sides by the a_(n-1).

$a_n=-3a_{n-1}$ where $a_1=2$

5 0

4 years ago

Read 2 more answers

In each diagram below, determine whether the triangles are congruent, similar, but not congruent, or not similar. If you claim t

Nadya [2.5K]

Part a

Angle ABC = angle CDA (given by the angle markers)

Angle BAC = angle DCA (alternate interior angles)

Segment AC = segment AC (reflexive property)

Through AAS (angle angle side) we can prove the two triangles are congruent. We have a pair of congruent angles, and we have a pair of congruent sides that are not between the previously mentioned angles.

If two triangles are congruent, they are always similar as well (scale factor = 1).

The same cannot be said the other way around. Not all similar triangles are congruent.

<h3>Answer: Congruent</h3>

======================================================

Part b

Angle FGH = angle JIH (both shown to be 50 degrees)

Angle FHG = angle JHI (vertical angles)

We have enough information to prove the triangles to be similar triangles. This is through the AA (angle angle) similarity rule. Since FG and JI are different lengths, this means the triangles are not congruent.

<h3>Answer: Similar but not congruent</h3>

======================================================

Part c

For each right triangle shown, divide the longer leg over the shorter leg

larger triangle: (long leg)/(short leg) = 6/3 = 2

smaller triangle: (long leg)/(short leg) = 3/2 = 1.5

The two results are different, so the sides are not in proportion to one another, therefore the triangles are not similar.

Any triangles that are not similar will also never be congruent.

<h3>Answer: Not similar</h3>

======================================================

Part d

Use the pythagorean theorem to find that PQ = 5 and KL = 12

We have two triangles with corresponding sides that are the same length

So we use the SSS (side side side) triangle congruence theorem to prove the triangles congruent. The triangles are also similar triangles (scale factor = 1)

<h3>Answer: Congruent</h3>

======================================================

<h3>Summary of the answers:</h3><h3>a. Congruent</h3><h3>b. Similar but not congruent</h3><h3>c. Not similar</h3><h3>d. Congruent </h3>

4 0

3 years ago

FOR MATH FINAL WILL GIVE BRAINLIEST FOR CORRECT ANSWER

ruslelena [56]

Answer:

180 cm³

Step-by-step explanation:

2 x 5 x 6 = 30 x 2 = 60

3 x 8 x 5 = 40 x 3 = 120

120 + 60 = 180

6 0

3 years ago

Find the laplace transform of f(t) = cosh kt = (e kt + e −kt)/2

iren2701 [21]

Hello there, hope I can help!

I assume you mean $L\left\{\frac{ekt+e-kt}{2}\right\}$
With that, let's begin

$\frac{ekt+e-kt}{2}=\frac{ekt}{2}+\frac{e}{2}-\frac{kt}{2} \ \textgreater \ L\left\{\frac{ekt}{2}-\frac{kt}{2}+\frac{e}{2}\right\}$

$\mathrm{Use\:the\:linearity\:property\:of\:Laplace\:Transform}$
$\mathrm{For\:functions\:}f\left(t\right),\:g\left(t\right)\mathrm{\:and\:constants\:}a,\:b$
$L\left\{a\cdot f\left(t\right)+b\cdot g\left(t\right)\right\}=a\cdot L\left\{f\left(t\right)\right\}+b\cdot L\left\{g\left(t\right)\right\}$
$\frac{ek}{2}L\left\{t\right\}+L\left\{\frac{e}{2}\right\}-\frac{k}{2}L\left\{t\right\}$

$L\left\{t\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{t\right\}=\frac{1}{s^2} \ \textgreater \ L\left\{t\right\}=\frac{1}{s^2}$

$L\left\{\frac{e}{2}\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{a\right\}=\frac{a}{s} \ \textgreater \ L\left\{\frac{e}{2}\right\}=\frac{\frac{e}{2}}{s} \ \textgreater \ \frac{e}{2s}$

$\frac{ek}{2}\cdot \frac{1}{s^2}+\frac{e}{2s}-\frac{k}{2}\cdot \frac{1}{s^2}$

$\frac{ek}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{ek\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{ek}{2s^2}$

$\frac{k}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{k\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{k}{2s^2}$

$\frac{ek}{2s^2}+\frac{e}{2s}-\frac{k}{2s^2}$

Hope this helps!

3 0

4 years ago