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2 years ago

Simplify the fraction and state the excluded value(s).

Mathematics

1 answer:

stira [4]2 years ago

8 0

Answer:

$\displaystyle \frac{7x^2 + 4x - 20}{5x + 10} = \frac{7x - 10}{5}, x \neq -2$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Terms/Coefficients

Factoring

Calculus

Discontinuities

Removable (Holes)
Jump (Piece-wise functions)
Infinite (Asymptotes)

Step-by-step explanation:

Step 1: Define

$\displaystyle \frac{7x^2 + 4x - 20}{5x + 10}$

Step 2: Simplify

[Frac - Numerator] Factor quadratic: $\displaystyle \frac{(7x - 10)(x + 2)}{5x + 10}$
[Frac - Denominator] Factor GCF: $\displaystyle \frac{(7x - 10)(x + 2)}{5(x + 2)}$
[Frac] Divide/Simplify: $\displaystyle \frac{(7x - 10)}{5}, x \neq -2$

When we divide (x + 2), we would have a removable discontinuity. If we were to graph the original function, we would see at x = -2 there would be a hole in the graph.

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Solve log base 6 (x-6) - log base 6 (x + 4) = 2

Ray Of Light [21]

Answer:

no solutions

Step-by-step explanation:

Since the two terms have the same base, we are able to use the rule for subtracting logarithms:

$log_{b}(x) - log_{b}(y) = log_{b}(\frac{x}{y} )$

Therefore, the equation can be written as:

$log_{6}(\frac{x-6}{x+4} )=2$

By using the definition of a logarithm we can say that:

$\frac{x-6}{x+4} = 6^{2}\\\frac{x-6}{x+4} = 36\\x -6 = 36x+144\\35x = -150\\x =-\frac{30}{7}$

When plugging this solution in, you find that the term $log_{6}(x-6)$ has x-6 evaluate to a number less than 0. This is not included in the domain of log functions, so $-\frac{30}{7}$ is not a valid solution. This means that there are no solutions.

4 0

1 year ago

Short Response

garik1379 [7]

Answer:

(a)2(89x+84)

(b) $2(89x+84-x^2\pi)$

Step-by-step explanation:

The dimensions of the larger rectangular field are:

Length=5x + 12; Width = 9x + 14.

The dimensions of the smaller rectangular soccer field are:

Length=5x; Width = 9x.

(a)Area of the part of the field that is outside the soccer field

=Area of the larger rectangular field - Area of the Soccer Field

=(5x+12)(9x+14)-5x(9x)

=(5x)(9x)+70x+108x+168-5x(9x)

=178x+168

=2(89x+84)

(b)Radius of the Semicircular Fountain =2x

From Part (a),

Area of the larger rectangular field - Area of the Soccer Field=178x+168

Area of the Semicircular Fountain = $\dfrac{\pi r^2}{2} =\dfrac{\pi (2x)^2}{2} =\dfrac{4x^2\pi}{2} =2x^2\pi$

Area of the Field that does not include the soccer field or the fountain.

=Area of the larger rectangular field - Area of the Soccer Field-Area of the Semicircular Fountain

$=178x+168-2x^2\pi\\=2(89x+84-x^2\pi)$

8 0

3 years ago

Sigma notation can someone help me understand this and give an example...

timofeeve [1]

Answer:

Simple sum. The symbol Σ (sigma) is generally used to denote a sum of multiple terms. This symbol is generally accompanied by an index that varies to encompass all terms that must be considered in the sum.