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Charra [1.4K]
3 years ago
8

Simplify the fraction and state the excluded value(s).

Mathematics
1 answer:
stira [4]3 years ago
8 0

Answer:

\displaystyle \frac{7x^2 + 4x - 20}{5x + 10} = \frac{7x - 10}{5}, x \neq -2

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Terms/Coefficients
  • Factoring

<u>Calculus</u>

Discontinuities

  • Removable (Holes)
  • Jump (Piece-wise functions)
  • Infinite (Asymptotes)

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle \frac{7x^2 + 4x - 20}{5x + 10}<u />

<u />

<u>Step 2: Simplify</u>

  1. [Frac - Numerator] Factor quadratic:                    \displaystyle \frac{(7x - 10)(x + 2)}{5x + 10}
  2. [Frac - Denominator] Factor GCF:                        \displaystyle \frac{(7x - 10)(x + 2)}{5(x + 2)}
  3. [Frac] Divide/Simplify:                                           \displaystyle \frac{(7x - 10)}{5}, x \neq -2

When we divide (x + 2), we would have a <em>removable</em> <em>discontinuity</em>. If we were to graph the original function, we would see at x = -2 there would be a hole in the graph.

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2 years ago
Graph f(x) =-2x^+16x-30 by factoring to find the solutions, then find the coordinates of the vertex, and the axis of symmetry. I
fredd [130]

Answer:

<em>Observe attached image</em>

<em>Function zeros:</em>

(3, 0), (5, 0)

<em>Vertex:</em>

(4, 2)

<em>Axis of symmetry:</em>

<em>x =4</em>

Step-by-step explanation:

<u>First factorize the function</u>

f (x) = -2x ^ 2 + 16x-30

<em>Take -2 as a common factor.</em>

-2(x ^ 2 -8x +15)

<em>Now factor the expression x ^ 2 -8x +15</em>

You must find two numbers that when you add them, obtain the result -8 and multiplying those numbers results in 15.

These numbers are -5 and -3

Then we can factor the expression in the following way:

f (x) = -2(x-5)(x-3)

<em><u>The quadratic function cuts the x-axis at </u></em><em>x = 3 and at x = 5.</em>

Now we find the coordinates of the vertex.

For a function of the form ax ^ 2 + bx + c the x coordinate of its vertex is:

x = \frac{-b}{2a}

In the function f (x) = -2x ^ 2 + 16x-30

a = -2\\b = 16\\c = 30

<u>Then the vertice is:</u>

x = \frac{-16}{2(-2)}\\\\x = 4

The y coordinate of the symmetry axis is

y = f (4) = -2 (4) ^ 2 +16 (4) -30\\\\y = 2

The axis of symmetry is a vertical line that cuts the parabola in two equal halves. This axis of symmetry always passes through the vertex.

<u>Then the axis of symmetry is the line</u>

x = 4

<u>The solutions and the vertice written as ordered pairs are:</u>

<em>Function zeros:</em>

(3, 0), (5, 0)

<em>Vertex:</em>

(4, 2)

6 0
3 years ago
Which is the asymptote of the graph? y=0, y=1, y=2, y=3
nordsb [41]

Answer:

the asymptote would be zero because the graph is approaching zero, but never actually touches it.

8 0
3 years ago
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