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vesna_86 [32]
3 years ago
9

ANSWER WITH WORK SHOWN or I will issue a special Perma Ban Bot to conclude a Permanant IP Ban to your account.

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
4 0

Answer:

  • 4) 6m, 8m, 10m

Step-by-step explanation:

<u><em>Use Pythagorean to determine the answer</em></u>

#4

  • 6² + 8² = 10²
  • 36 + 64 = 100
  • 100 = 100,
  • <u>yes</u>

#5

  • 8m + 16m = 24m, hence <u>no</u> triangle formed as per triangle inequality theorem

#6

  • 20² + 21² = 28²
  • 400 + 441 = 784
  • 841 ≠ 784,
  • <u>no</u>
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Kay [80]
As decimals lets look at them:)
7/8 = 0.875
3/4 = 0.75

In this case 7/8 is actually bigger. 

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Last week caroline worked 8 hours each day and she worked 5 days that week she earned $440 pounds so per hour she earned £11
IRISSAK [1]

Answer:

30%

Step-by-step explanation:

this week:

4 × 7 = 28 hours

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132/440 × 100

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Who is the president of USA
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3 years ago
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One measure of an athlete’s ability is the height of his or her vertical leap. Many professional basketball players are known fo
almond37 [142]

Answer:

(1) P(\bar X < 26 inches) = 0.0436

(2) P(27.5 inches < \bar X < 28.5 inches) = 0.2812

Step-by-step explanation:

We are given that the mean vertical leap of all NBA players is 28 inches. Suppose the standard deviation is 7 inches and 36 NBA players are selected at random.

Firstly, Let \bar X = mean vertical leap for the 36 players

Assuming the data follows normal distribution; so the z score probability distribution for sample mean is given by;

            Z = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean vertical  leap = 28 inches

            \sigma = standard deviation = 7 inches

            n = sample of NBA player = 36

(1) Probability that the mean vertical leap for the 36 players will be less than 26 inches is given by = P(\bar X < 26 inches)

   P(\bar X < 26) = P( \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < \frac{26-28}{\frac{7}{\sqrt{36} } } ) = P(Z < -1.71) = 1 - P(Z \leq 1.71)

                                                 = 1 - 0.95637 = 0.0436

(2) <em>Now, here sample of NBA players is 26 so n = 26.</em>

Probability that the mean vertical leap for the 26 players will be between 27.5 and 28.5 inches is given by = P(27.5 inches < \bar X < 28.5 inches) = P(\bar X < 28.5 inches) - P(\bar X \leq 27.5 inches)

    P(\bar X < 28.5) = P( \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < \frac{28.5-28}{\frac{7}{\sqrt{26} } } ) = P(Z < 0.36) = 0.64058 {using z table}                      

    P(\bar X \leq 27.5) = P( \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } \leq \frac{27.5-28}{\frac{7}{\sqrt{26} } } ) = P(Z \leq -0.36) = 1 - P(Z < 0.36)

                                                        = 1 - 0.64058 = 0.35942

Therefore, P(27.5 inches < \bar X < 28.5 inches) = 0.64058 - 0.35942 = 0.2812

6 0
3 years ago
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