The most common method for fitting a regression line is the method of least-squares. This method calculates the best-fitting line for the observed data by minimizing the sum of the squares of the vertical deviations from each data point to the line (if a point lies on the fitted line exactly, then its vertical deviation is 0). Because the deviations are first squared, then summed, there are no cancellations between positive and negative values.Example<span>The dataset "Televisions, Physicians, and Life Expectancy" contains, among other variables, the number of people per television set and the number of people per physician for 40 countries. Since both variables probably reflect the level of wealth in each country, it is reasonable to assume that there is some positive association between them. After removing 8 countries with missing values from the dataset, the remaining 32 countries have a correlation coefficient of 0.852 for number of people per television set and number of people per physician. The </span>r²<span> value is 0.726 (the square of the correlation coefficient), indicating that 72.6% of the variation in one variable may be explained by the other. </span><span>(Note: see correlation for more detail.)</span><span> Suppose we choose to consider number of people per television set as the explanatory variable, and number of people per physician as the dependent variable. Using the MINITAB "REGRESS" command gives the following results:</span>
<span>The regression equation is People.Phys. = 1019 + 56.2 People.Tel.</span>
Answer:
Speed = Distance/time in km/h
a) 18 feet in 20 minutes
0.0054864 km/0.333333hours
=0.01645921645 km/h
b) 90 feet in 2.5 hours
0.027432km/2.5
=0.0109728 km/h
c) 20 yards in 1.5 hours
0.018288km/1.5
=0.012192 km/h
d) 3 2/3 yards in 15 minutes
0.003352800000003048km/0.25hours
=0.0134112
So I think its safe to say that A is the fastest in comparison
Sin^2 + cos^2 =1
COS t= .9897
Since tan=sin/cos < 0 so cos = -.9897
Tan = sin/cos = (1/7)/(-.9897)= -.1443
Answer:
8
Step-by-step explanation:
Key to this question is assume that each exchange preserves the total dollar amount of Nick’s money.
If He exchanges all his $5 bills for $1 bills, it means that a $5 bill will result in 5 $1 bills as such, if he had x number of $5 bill, after the exchange, he would have 5x $1 bills.
then all his $20 bills for $5 bills, it means that for each $20 bill, he gets 4 $5 bills which means that if he had y number of $5 bills, after the exchange, he would have 4y $5 bills.
and finally all his $100 bills for $20 bills, then he must have received 5 $20 bills for each $100 such that if he had z number of $100 bills before the exchange, he would have 5z number of $20 bills after the exchange. Given that originally he had 17 bills and later 77 bills then
x + y + z = 17
5x + 4y + 5z = 77
Multiplying the first equation by 5,
5x + 5y + 5z = 85
5x + 4y + 5z = 77
subtract 2 from 1
y = 8
