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3 years ago

Use the power-reducing formulas to rewrite each of the expressions in terms of the first power of the cosine. Sin^4cos^4

Mathematics

1 answer:

Katen [24]3 years ago

6 0

Answer:

1/128 * (3 - 4cos2x + cos4x)

Step-by-step explanation:

See attachment for steps

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RideAnS [48]

Answer:

DISTANCE=RATE*TIME. THEREFORE

X=3.6*1/6+4.2*1/6 (1/6 HOUR=10 MIN)

X=.6+.7

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Step-by-step explanation:

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Find the slope of the line passing through the points(3,-9) and(2,-2) .

tino4ka555 [31]

Answer:

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Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-2-(-9))/(2-3)

m=(-2+9)/-1

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3 years ago

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Step-by-step explanation:

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For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

ICE Princess25 [194]

Answer:

Part a) The area of the figure is $\frac{9}{2}(4+\pi )\ cm^{2}$

Part b) The perimeter of the figure is $3(2+2\sqrt{2}+ \pi)\ cm$

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

<u>Find the area of the figure ABC</u>

we have

$AB=6\ cm, BC=6\ cm$

The area of the half square ABC is equal to find the area of triangle ABC

$A1=\frac{1}{2}*6*6=18\ cm^{2}$

<u>Find the area of the semicircle</u>

The area of the semicircle is equal to

$A2=\pi r^{2}/2$

we have that

$r=6/2=3\ cm$

substitute

$A2=\pi (3)^{2}/2$

$A2=(9/2) \pi\ cm^{2}$

The area of the figure is equal to

$18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}$

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

$P=AB+AC+length\ CB$

we have

$AB=6\ cm$

Applying Pythagoras theorem

$AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm$

Remember that

the circumference of a semicircle is equal to

$C=\frac{1}{2}2\pi r=\pi r$

$r=6/2=3\ cm$

$C=\pi(3)$

$C=3 \pi\ cm$

The perimeter of the figure is equal to

$P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm$

Simplify

$P=3(2+2\sqrt{2}+ \pi)\ cm$

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3 years ago