Answer:
The solution to the equation is:
Option c. b=0 and b=4
Step-by-step explanation:
5 / (3b^3-2b^2-5) = 2 / (b^3-2)
Cross multiplication:
5(b^3-2)=2(3b^3-2b^2-5)
Applying distributive property both sides of the equation to eliminate the parentheses:
5(b^3)-5(2)=2(3b^3)-2(2b^2)-2(5)
Multiplying:
5b^3-10=6b^3-4b^2-10
Passing all the terms to the right side of the equation: Subtracting 5b^3 and adding 6 both sides of the equation:
5b^3-10-5b^3+10=6b^3-4b^2-10-5b^3+10
Adding like terms:
0=b^3-4b^2
b^3-4b^2=0
Getting common factor b^2 on the left side of the equation:
b^2 (b^3/b^2-4b^2/b^2)=0
b^2 (b-4) = 0
Two solutions:
(1) b^2=0
Solving for b: Square root both sides of the equation:
sqrt(b^2)=sqrt(0)
Square root:
b=0
(2) b-4=0
Solving for b: Adding 4 both sides of the equation:
b-4+4=0+4
Adding like terms:
b=4
The solution of the equation is: b=0 and b=4 (Option c)
Answer:
Then the best way to phrase it would be to jump right into the question without I need your help, because saying so makes it sound as though you have more of an urgent, sensitive, personal problem than a simple question or two (they might be a bit taken aback by the phrase).
However, if you have several questions (let's say more than 2), or if you just want to sound a bit more polite, you could preface the content with a phrase like I was wondering I you might be able to answer a few questions of mine, or, I have a few questions that I was hoping you might be able to help me with.
Answer:
For the domain indicated, the range is {-11, -7, -3, 1, 5}
Step-by-step explanation:
Given the indicated domain of f(x) you have to replace the values in the function to find the range (the "y" values of the function).
f(-2) = 5
f(0) = 1
f(2) = -3
f(4) = -7
f(6) = -11.
So the range for this domain is {-11, -7, -3, 1, 5}
Answer:
There is something already at the positive 2 place and you are just subtracting 2 because of (-2)
I hope that helps :)
Step-by-step explanation:
plz mark B R A I N L I E S T
