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3 years ago

Use the power-reducing formulas to rewrite each of the expressions in terms of the first power of the cosine. Sin^4cos^4

Mathematics

1 answer:

Katen [24]3 years ago

6 0

Answer:

1/128 * (3 - 4cos2x + cos4x)

Step-by-step explanation:

See attachment for steps

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Has anybody gotten a 100% on their FLVS Math segment exam?

Flura [38]

Answer:

i have

Step-by-step explanation:

3 0

3 years ago

Compare the following fraction 4/3 and 5/2 -3/2. -4/5

zavuch27 [327]

Answer:

Step-by-step explanation:

to compare them, we need to convert them into like fractions

4/3 and 5/2

lcm of 3 and 2 is 6

4/3 × 2/2 = 8/6

5/2 × 3/3 = 15/6

15/6 is greater than 8/6

so 5/2 is greater than 4/3

similarly,

-3/2 and -4/5

we need to convert them into like fractions

lcm of 2 and 5 is 10

-3/2 × 5/5 = -15/10

-4/5 × 2/2 = -8/10

-8/10 is greater than -15/10

so -4/5 is greater than -3/2

Hope this helps

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5 0

3 years ago

PLEASE HELP RN....i’m stuck

Dmitry_Shevchenko [17]

Answer:

612+c>=2000

Step-by-step explanation:

7 0

3 years ago

The terminal side of Ø is in quadrant II and cos ø = -5/13 What is sin ø?

Sliva [168]

the value of sin ∅ is 12/ 13

<h3>Quadrants and the "cast" Rule:</h3>

In the first quadrant, the values for sin, cos, and tan are positive.

In the second quadrant, the values for sin are positive only.

In the third quadrant, the values for tan are positive only.

In the fourth quadrant, the values for cos are positive only.

From the given question,

We have, cos ∅= 5/13

From the trigonometric identities, we have that

$sin^2\alpha + cos^2\alpha = 1$

Then , let's substitute the value of cos ∅

$sin^2\alpha +(\frac{-5}{13} )^2 = 1$

Let make sin the subject of formula and find the squares of the fraction

sin²∅ = $1 - \frac{25}{169}$

Find the LCM

sin²∅ = $\frac{169 - 25}{169}$

Find the difference

sin²∅ = $\frac{144}{169}$

Find the square root

sin∅ = $\sqrt{\frac{144}{159} }$

sin∅ = $\frac{12}{13}$

In quadrant II , sin is positive, so we have

sin ∅ = 12/ 13

Thus, the value of sin ∅ is 12/ 13

Learn more about quadrant here:

brainly.com/question/863849

#SPJ1

7 0

2 years ago

What are the like terms in the expression below 2x³+5y - 6x² - 4y² + 8x²y - x³

Bas_tet [7]

Answer:

$x^{3} +5y-6x^{2} -4y^{2} +8x^{2} y$

Step-by-step explanation:

$2x^{3} +5y-6x^{2} -4y^{2} +8x^{2} y-x^{3}$

$(2x^{3} -x^{3} )$

$x^{3} +5y-6x^{2} -4y^{2} +8x^{2} y$

7 0

3 years ago