Answer:
Step-by-step explanation:
If Thaddeus drives the whole 16 hours, the distance between them is ...
distance = speed · time
distance = 20 mi/h · 16 h
distance = 320 miles.
It is 45 miles more than that. For each hour that Ian drives, their separation distance increases by (25 mph -20 mph)·(1 h) = 5 mi. Then Ian must have driven ...
(45 mi)/(5 mi/h) = 9 h
The rest of the 16 hours is the time that Thaddeus drove: 7 hours.
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Let x represent the time Ian drives. Then 16-x is the time Thaddeus drives. Their total distance driven is ...
distance = speed · time
365 mi = (25 mi/h)(x) + (20 mi/h)(16 h -x)
45 mi = (5 mi/h)(x) . . . . . . . . subtract 320 miles, collect terms
(45 mi)/(5 mi/h) = x = 9 h . . . . . . divide by the coefficient of x
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<em>Comment on the solution</em>
You may notice a similarity between the solution of this equation and the verbal discussion above. (That is intentional.) It works well to let a variable represent the amount of the highest contributor. Here, that is Ian's time, since he is driving at the fastest speed.
Answer:
n = 1
Step-by-step explanation:
2n-10 = -8
Then add 10 to both sides
2n = 2
Divide both sides by two
n = 1
Step-by-step explanation:
for a it's y=12x+60
for b it's y=1x+21
for c it would be) 40-70=-30/1-3=-2 and then divide -30/-2 is 15.
for d it would be y=20x+20
it would be ethier a or d
Could you get a closer picture?
Answer:
what form?
Step-by-step explanation:
