
To find the gradient of the tangent, we must first differentiate the function.

The gradient at x = 0 is given by evaluating f'(0).

The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.
The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so

Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).

So the point (0, -1) lies on the tangent. Substituting into the tangent equation:
a.) N
b.)A
c.) N
d.) S
e.) S
f.)A
g.) S
i don’t need anything, just helping you all! hope it’s correct!
Answer:
the answer is 205
Step-by-step explanation:
%/100 X is/of 177 IS 60% of the students. so you put 60/100 and multiply 177/X 177X100=17700. Now divide that by 60 and you come up with 28.33. This obviously is not the answer so you add 28 (does not round up to 29) to 177 and you get 205.
We are asked to find the equivalent of the expression given:
(3m⁻² n)⁻³
-----------
6mn⁻²
Perform distribution of power using power rule such as shown below:
3⁻³ m⁻²*⁻³n⁻³
-----------------
6mn⁻²
Perform product and quotient rule such as shown below:
m⁶ n²
--------
3³ *6*m*n³
Simplify,
m⁵
--------
162n
The answer is m⁵/162n.