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Fiesta28 [93]
3 years ago
15

For a population with a mean of 40 and a standard deviation of 8 find the z-score corresponding to each of the following samples

.
X = 34 for a sample of n = 1 score:

M = 34 for a sample of n = 4

M = 34 for a sample of n = 16
Mathematics
1 answer:
aleksley [76]3 years ago
3 0

Answer:

a) -0.75

b) -1.5

c) -3

Step-by-step explanation:

The question asks to convert a given value to z score with different sample sizes.

<u>We are given:</u>

Population Mean = u = 40

and

Standard deviation = s = 8

The task is to convert 34 to z-score using 3 different sample sizes.

For a given sample size "n", the formula to calculate the z-score is:

z=\frac{x-u}{\frac{s}{\sqrt{n} } }

For x = 34 and n=1, we get:

z-score=\frac{34-40}{\frac{8}{\sqrt{1} } } = -0.75

For x = 34 and n = 4, we get:

z-score=\frac{34-40}{\frac{8}{\sqrt{4} } } = -1.5

For x = 34 and n = 16, we get:

z-score=\frac{34-40}{\frac{8}{\sqrt{16} } } = -3

From here we can see that increasing the sample sizes increases the magnitude of z-score.

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For the first one about Jack the answer to A is 14, 21, 30 and for b the answer is 22. Now for Maria the answer for A is 24 , 40 , 80 and for b it's 8

Step-by-step explanation:

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A pie was cut into 8 equal slices if Ruben ate 3/4 of the pie how many slices did he eat?
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Answer:

Ruben ate 6 pieces out of 8.

Step-by-step explanation:

We will understand 3/4 first. If we divide a pie into 4 pieces then Ruben ate 3 pieces of pie.

Further If we divide these 4 and 3 pieces to 8 and 6 then Ruben will eat 6 pieces out of 8.

Now we will show this mathematically

\frac{3}{4}=\frac{3}{4}\times \frac{2}{2}=\frac{3\times2}{4\times2}=\frac{6}{8}

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Read 2 more answers
Which of the following equations could be th equation to represent the given graph? Make sure you explain your answer thoroughly
Alex17521 [72]

Answer:

Option (C) is correct.

Step-by-step explanation:

The given options of the possible equation for the graph are as follows:

(A) y=2\left(\frac{3}{2}\right)^x \\\\(B) y=-2\left(\frac{3}{2}\right)^{-x} \\\\(C) y=2\left(\frac{2}{3}\right)^x \\\\(D) y=-2\left(\frac{2}{3}\right)^{-x} \\\\

The given graph is decreasing and at x=0, y=2.

So, first checking the value of the given options for x=0

(A) y=2\left(\frac{3}{2}\right)^0=2\times 1= 2 \\\\(B) y=--2\left(\frac{3}{2}\right)^{-0}= -2\times 1= -2 \; (not\; possible) \\\\(C) y=2\left(\frac{2}{3}\right)^0= 2\times 1= 2 \\\\(D) y=2\left(\frac{2}{3}\right)^{-0} = -2\times 1= -2 \; (not\; possible)

As, for x=0, y=2, so options (C) and (D) are not possible, so rejected.

Now, checking the nature (increasing or decreasing) of the given equation by differentiating it.

For option (A),

\frac{dy}{dx}=2\left(\frac{3}{2}\right)^{x}\times \ln\left(\frac{3}{2}\right)

As \ln \left(\frac{3}{2}\right)=\ln(1.5)>0 \;and\; \left(\frac{3}{2}\right)^{x} >0

So, \frac{dy}{dx}>0

Therefore, the function in option (A) is increasing function.

Similarly, for option (C),

\frac{dy}{dx}=2\left(\frac{2}{3}\right)^{x}\times \ln\left(\frac{2}{3}\right)

As \ln \left(\frac{2}{3}\right)=\ln(0.67)0

So, \frac{dy}{dx}

Therefore, the function in option (C) is decreasing function.

As the given graph is decreasing, so, (C)  representsy=2\left(\frac{2}{3}\right)^x the given graph.

Hence, option (C) is correct.

6 0
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