We are going to build a snake bot using 6 different segments how many different snake bots can we make
1 answer:
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<h3>Answer: Choice B</h3>
Explanation:
Cosine is positive in quadrants I and IV, but quadrant IV isn't shaded in so we can rule out choice A.
Sine is positive in quadrants I and II. So far it looks like choice B could work. In fact, it's the answer because sin(pi/6) = 1/2 and sin(5pi/6) = 1/2. So if 0 ≤ sin(x) < 1/2, then we'd shade the region between theta = 0 and theta = pi/6; as well as the region from theta = 5pi/6 to theta = pi.
Choice C is ruled out because tangent is positive in quadrants I and III, but quadrant III isn't shaded.
Choice D is ruled out for similar reasoning as choice A. Recall that
Answer:
The equation is at a rate of -23%.
Step-by-step explanation:
Decay can be represented by the equation . We can find the rate at which it decays by using t=3 hours and A=3000. This means
in this context.
After substituting, we divided by 6000 to each side to get 0.5 on the left. Now to solve for r, we will take the natural log of both sides and use log rules to isolate r.
We know so we were able to cancel it out and divide both sides by 3.
We solve with a calculator
We change -0.23 into a percent by multiplying by 100 to get -23% as the rate.
The equation is