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svlad2 [7]
3 years ago
8

Last one i think if not i will post the last one this is confusing

Mathematics
2 answers:
Jobisdone [24]3 years ago
8 0

Answer:

45 units

Step-by-step explanation:

  1. Expression: |-34 + 11|
  2. Simplify: 34 + 11
  3. 34 + 11 = 45 units

I hope this helps!

maria [59]3 years ago
5 0

Answer: 23

Step-by-step explanation: Because you do 34-11

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I need help... I honestly don’t know.
Serhud [2]

Answer:

∡ABC=55°

Step-by-step explanation:

<u>Step 1: Identify all angles</u>

∠A=(x+45)°

∠B=(6x+5)°

∠C=(3x)°

∠ABC=(180-∠B)°=(180-(6x+5))°

<u>Step 2: Use the Triangle Angle Sum Theorem</u>

∠A+∠ABC+∠C=180°

(x+45)+(180-(6x+5))+(3x)=180

x+45+180-6x-5+3x=180

-2x+45+180-5=180

-2x+45-5=0

-2x+40=0

-2x=-40

x=20

<u>Step 3: Plug in x=20 for ∠ABC</u>

∠ABC=(180-(6x+5))°

(180-6(20)-5)°

(180-120-5)°

(60-5)°

55°

So ∡ABC=55°

8 0
3 years ago
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Help I don’t get it at all
Naily [24]
The answer to your question is n is equal to 70
5 0
3 years ago
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if i wanted to make a 40,000 payment in one year with a 5% annual interest rate, how much should i invest now?
IRINA_888 [86]

Answer:

38,095.24

Step-by-step explanation:

40,000 = P(1 + 0.05)^1

P = 40,000/1.05

P = 38095.2380952

5 0
3 years ago
Consider the function ​f(x)equalscosine left parenthesis x squared right parenthesis. a. Differentiate the Taylor series about 0
dybincka [34]

I suppose you mean

f(x)=\cos(x^2)

Recall that

\cos x=\displaystyle\sum_{n=0}^\infty(-1)^n\frac{x^{2n}}{(2n)!}

which converges everywhere. Then by substitution,

\cos(x^2)=\displaystyle\sum_{n=0}^\infty(-1)^n\frac{(x^2)^{2n}}{(2n)!}=\sum_{n=0}^\infty(-1)^n\frac{x^{4n}}{(2n)!}

which also converges everywhere (and we can confirm this via the ratio test, for instance).

a. Differentiating the Taylor series gives

f'(x)=\displaystyle4\sum_{n=1}^\infty(-1)^n\frac{nx^{4n-1}}{(2n)!}

(starting at n=1 because the summand is 0 when n=0)

b. Naturally, the differentiated series represents

f'(x)=-2x\sin(x^2)

To see this, recalling the series for \sin x, we know

\sin(x^2)=\displaystyle\sum_{n=0}^\infty(-1)^{n-1}\frac{x^{4n+2}}{(2n+1)!}

Multiplying by -2x gives

-x\sin(x^2)=\displaystyle2x\sum_{n=0}^\infty(-1)^n\frac{x^{4n}}{(2n+1)!}

and from here,

-2x\sin(x^2)=\displaystyle 2x\sum_{n=0}^\infty(-1)^n\frac{2nx^{4n}}{(2n)(2n+1)!}

-2x\sin(x^2)=\displaystyle 4x\sum_{n=0}^\infty(-1)^n\frac{nx^{4n}}{(2n)!}=f'(x)

c. This series also converges everywhere. By the ratio test, the series converges if

\displaystyle\lim_{n\to\infty}\left|\frac{(-1)^{n+1}\frac{(n+1)x^{4(n+1)}}{(2(n+1))!}}{(-1)^n\frac{nx^{4n}}{(2n)!}}\right|=|x|\lim_{n\to\infty}\frac{\frac{n+1}{(2n+2)!}}{\frac n{(2n)!}}=|x|\lim_{n\to\infty}\frac{n+1}{n(2n+2)(2n+1)}

The limit is 0, so any choice of x satisfies the convergence condition.

3 0
3 years ago
What are Examples of 100 ML or less at a grocery store ?
tekilochka [14]
You could do a few (3-4)milk  carton
5 0
3 years ago
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