Answer:
the C one is 18in and the E one is 12in
Step-by-step explanation:
Answer:
![\huge\boxed{\sf-2x+28}\\\\\huge\boxed{\sf 10x-4}\\\\\huge\boxed{\sf 56-5x}\\\\\huge\boxed{\sf x-13}](https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7B%5Csf-2x%2B28%7D%5C%5C%5C%5C%5Chuge%5Cboxed%7B%5Csf%2010x-4%7D%5C%5C%5C%5C%5Chuge%5Cboxed%7B%5Csf%2056-5x%7D%5C%5C%5C%5C%5Chuge%5Cboxed%7B%5Csf%20x-13%7D)
Step-by-step explanation:
![\sf 2x + 4(7-x) \\\\Resolving \ Parenthesis\\\\2x + 28-4x \\\\Combining\ like\ terms\\\\2x-4x +28\\\\-2x + 28\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%202x%20%2B%204%287-x%29%20%20%5C%5C%5C%5CResolving%20%5C%20Parenthesis%5C%5C%5C%5C2x%20%2B%2028-4x%20%5C%5C%5C%5CCombining%5C%20like%5C%20terms%5C%5C%5C%5C2x-4x%20%2B28%5C%5C%5C%5C-2x%20%2B%2028%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
![\sf \\12x-(4+2x)\\\\12x-4-2x\\\\Combining \ like \ terms\\\\12x-2x - 4\\\\10x-4 \\\\\rule[22]{225}{2} \\2(10-x)+3(12-x) \\\\Resolving \ Parenthesis\\\\20-2x + 36 -3x\\\\Combining \ like \ terms\\\\20+36 -2x-3x\\\\56 - 5x \\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20%5C%5C12x-%284%2B2x%29%5C%5C%5C%5C12x-4-2x%5C%5C%5C%5CCombining%20%5C%20like%20%5C%20terms%5C%5C%5C%5C12x-2x%20-%204%5C%5C%5C%5C10x-4%20%5C%5C%5C%5C%5Crule%5B22%5D%7B225%7D%7B2%7D%20%5C%5C2%2810-x%29%2B3%2812-x%29%20%5C%5C%5C%5CResolving%20%5C%20Parenthesis%5C%5C%5C%5C20-2x%20%2B%2036%20-3x%5C%5C%5C%5CCombining%20%5C%20like%20%5C%20terms%5C%5C%5C%5C20%2B36%20-2x-3x%5C%5C%5C%5C56%20-%205x%20%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
![\sf 7(x-1)-6(x+1)\\\\Resolving \ Parethesis\\\\7x-7-6x-6\\\\Combining \ like \ terms\\\\7x-6x-7-6\\\\x - 13\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%207%28x-1%29-6%28x%2B1%29%5C%5C%5C%5CResolving%20%5C%20Parethesis%5C%5C%5C%5C7x-7-6x-6%5C%5C%5C%5CCombining%20%5C%20like%20%5C%20terms%5C%5C%5C%5C7x-6x-7-6%5C%5C%5C%5Cx%20-%2013%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
~AnonymousHelper1807
to get the inverse of any expression, we start off by doing a quick switcheroo on the variables and then solve for "y".
![\stackrel{f(x)}{y}=\cfrac{1}{x^2}\implies \stackrel{\textit{quick switcheroo}}{x=\cfrac{1}{y^2}}\implies y^2=\cfrac{1}{x}\implies y=\sqrt{\cfrac{1}{x}}\implies \stackrel{f^{-1}(x)}{y}=\cfrac{1}{\sqrt{x}}](https://tex.z-dn.net/?f=%5Cstackrel%7Bf%28x%29%7D%7By%7D%3D%5Ccfrac%7B1%7D%7Bx%5E2%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bquick%20switcheroo%7D%7D%7Bx%3D%5Ccfrac%7B1%7D%7By%5E2%7D%7D%5Cimplies%20y%5E2%3D%5Ccfrac%7B1%7D%7Bx%7D%5Cimplies%20y%3D%5Csqrt%7B%5Ccfrac%7B1%7D%7Bx%7D%7D%5Cimplies%20%5Cstackrel%7Bf%5E%7B-1%7D%28x%29%7D%7By%7D%3D%5Ccfrac%7B1%7D%7B%5Csqrt%7Bx%7D%7D)