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Liula [17]
3 years ago
12

I need help solving this ​

Mathematics
1 answer:
MrRa [10]3 years ago
7 0

Answer:

I have no idea but it might be

YZ = XT

RS = XZ

XY = TZ

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Solve for x: 2 over 5 (x − 4) = 2x.<br><br> −8<br> negative 1 over 2<br> 1<br> −1
vlabodo [156]
2/5(x - 4) = 2x
2/5x - 8/5 = 2x....multiply everything by 5
2x - 8 = 10x
-8 = 10x - 2x
-8 = 8x
-8/8 = x
-1 = x <===
5 0
3 years ago
What do you think the answer is, Hurry.
Svet_ta [14]
The answer of this problem is A because 3 times 21 is 63 and then you plus 1 
which is 64 
4 0
3 years ago
Read 2 more answers
I need help with number patterns​
bija089 [108]

Answer:

what are the numbers at my guy

7 0
3 years ago
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A stack of 30 science flashcards includes a review card for each of the following: 10 insects, 8 trees, 8 flowers, and 4 birds.
Gnom [1K]

The probability of randomly selecting a tree or a flower is 8/15.

<h3>What is the probability?</h3>

Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.

The probability of randomly selecting a tree or a flower = (number of trees / total number of flash cards) + (number of flowers / total number of flash cards)

8/30 + 8/30 = 16/30  = 8/15

To learn more about probability, please check: brainly.com/question/13234031

#SPJ1

6 0
2 years ago
CAN SOMEONE HELP. i will give 150 points if some one can explain and solve you have to find the missing angle measures.
Tems11 [23]

Answer:

\angle ACB=40^{\circ}, \angle ABC=63^{\circ}

Step-by-step explanation:

Finding x:

We know that \angle DAB=180^{\circ}, because it's a straight line. So, \angle CAB=180^{\circ}-103^{\circ}=77^{\circ}.

We know that the sum of the angles of any triangle will be 180^{\circ}.

So, we have that (3x-14)+(3x+9)+77=180.

Combining like terms on the left gives 6x+72=180.

Subtracting 72 from both sides gives 6x=108.

Dividing both sides by 6 gives x=18.

Finding missing angle measures:

\angle ACB=3x-14=3(18)-14=54-14=40.

\angle ABC=3x+9=3(18)+9=54+9=63.

So, \angle ACB=40^{\circ} and \angle ABC=63^{\circ} and we're done!

Note: \angle ACB+\angle ABC=\angle CAD. Coincidence? If not, try and prove it!

7 0
3 years ago
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