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ELEN [110]
3 years ago
10

PLEASE HElP

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
4 0

Answer:

11 outfits

pairs means 2 so thats includes shoes pants besides shirts it doesn't pair. 5×2=10 6×2=12 so 10+12+8=30 30-19=11 ans

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use the graph that shows the averge number of the heartbeats for an active adult brown bear and hibernating brown bear
julia-pushkina [17]
<span>Given the graph that shows the average number of the heartbeats for an active adult brown bear and hibernating brown bear

Part a</span>.
What does the point (2, 120) represent on the graph?

From the graph the x axis represent the time in minutes while the y axis represent the number of heartbeats.

Therefore, point (2, 120) means that it takes an active adult brown bear an average of 2 minutes to have 120 heartbeat.


Part b.
What does the ratio of the y-coordinate to the x-coordinate for each pair of points on the graph represent?

From the graph the x axis represent the time in minutes while the y axis represent the number of heartbeats.

Therefore, the ratio of the y-coordinate to the x-coordinate for each pair of points on the graph represents the average number of heatbeats of an active brown dear and a hibernating brown dear per minute.


Part c.
Use the graph to find the bear’s average heart rate when it is active and when it is hibernating.

The bear's average heart rate is given by the ratio of the y-coordinate to the x-coordinate for each pair of points on the graph.

This can be obtained by taking any two points from the graph and taking the slope.

Recall that the slope of a line is given by
m= \frac{y_2-y_1}{x_2-x_1}

For the average hearbeat of an active brown bear, using the points (1.5, 90) and (2, 120), we calculate the average heat rate as follows:
Average heart rate = \frac{120-90}{2-1.5} = \frac{30}{0.5} =60 \ beats \ per \ minute

Also, for the average hearbeat of a hibernating brown bear, using the points (1.5, 18) and (2, 24), we calculate the average heat rate as follows:
Average heart rate = \frac{24-18}{2-1.5} = \frac{6}{0.5} =12 \ beats \ per \ minute
4 0
4 years ago
Please help! thank you to anyone who does:)
Sav [38]

Answer: it is th

Step-by-step explanation:

3 0
3 years ago
Jessie says to round 763 400 to the nearest ten thousand he will round to 770 000 is he right ?
skad [1K]
No because it's closer to 760,000
4 0
3 years ago
Read 2 more answers
Joe is a waiter at a local pizza parlor. He usually gets a tip from the table he waits on. The bill for one table comes to $34.
Aneli [31]
38 divided by x% equals= 
3 0
3 years ago
The union for a particular industry has determined that the standard deviation of the daily wages of its workers is $20. A rando
Sergeeva-Olga [200]

Answer:

The 90% confidence interval for the true mean daily wage of all union workers in the industry is ($118.6, $125.4). The lower limit is $118.6 and the upper limit is $125.4.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.645.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.645\frac{20}{\sqrt{90}} = 3.4

The lower end of the interval is the sample mean subtracted by M. So it is 122 - 3.4 = $118.6

The upper end of the interval is the sample mean added to M. So it is 122 + 3.4 = $125.4

The 90% confidence interval for the true mean daily wage of all union workers in the industry is ($118.6, $125.4). The lower limit is $118.6 and the upper limit is $125.4.

4 0
3 years ago
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