y = -2/-3x + 4/-3
y= ⅔x -4/3
if the line is parallel them m =⅔
so u have
y-5/x-4 = ⅔
3y-15= 2x-8
3y-2x =-8+15 = 7
-2x+3y=7 or 2x-3y=-7this is the standard form
while y= ⅔x +7/3 is the intercept form
To solve this question, you want to try to get the variable alone on one side.
So, your starting equation is 7a-3=3+6a. You want to subtract 6a from both sides of the equation, so that the variable a is only on the left side of the equation.
So, after subtracting, your equation looks like a-3=3. Next, you want to add 3 to both sides, to cancel out the -3 on the left side of the equation.
If performed correctly, your equation should be a=6.
Your final answer is a=6.
Answer:
y = x + 4
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c
Given
- 7x + 2y = 8 ( add 7x to both sides )
2y = 7x + 8 ( divide all 3 terms by 2 )
y = x + 4 ← in slope- intercept form
Identify the "a, b, c" values, find the axis of symmetry (AOS), and plug in the x-coordinate to find the y-coordinate.
a, b, c: y = ax² + bx + c → a = 2, b = -4, c = 1
AOS: x = = = = 1
y-coordinate: y = 2x² - 4x + 1 = 2(1)² - 4(1) + 1 = 2 - 4 + 1 = -1
Answer: (1, -1)