$x^4-2x^2-3=0\\
x^4+x^2-3x^2-3=0\\
x^2(x^2+1)-3(x^2+1)=0\\
(x^2-3)(x^2+1)=0\\
x^2-3=0 \vee x^2+1=0\\
x^2=3 \vee x^2=-1\\
x=-\sqrt3 \vee x=\sqrt3 \vee x=-i \vee x=i$

5 0

3 years ago

How do you calculate this?

Nimfa-mama [501]

Answer:

hdwhdbehqj

Step-by-step explanation:

223499

3344rbjee

4 0

3 years ago

Why does this system of equations have infinitely many solutions?

lapo4ka [179]

Step-by-step explanation:

I would say the one that says after eliminating a variable,the result is x=0

cause the zero can change into any number.

6 0

3 years ago

2(3) squared answer and steps.

olga55 [171]

Step-by-step explanation:

2(3)

2×3=6

6×6=36

36 is the correct answer i hope it helps you

4 0

3 years ago