So basically you just add the like terms to simplify the equation. You have 5q-p+p+1 you can cancel out the both p’s because one is negative and one is positive. That leaves you with 5q + 1 they are not like terms so you cannot simplify them so your simplified equation is 5q +1
Answer:
The margin of error M.O.E = 2.5%
Step-by-step explanation:
Given that;
The sample size = 1500
The sample proportion 
= 0.60
Confidencce interval = 0.95
The level of significance ∝ = 1 - C.I
= 1 - 0.95
= 0.05
The critical value:
(From the z tables)
The margin of error is calculated by using the formula:
M.O.E = 0.02479
M.O.E ≅ 0.025
The margin of error M.O.E = 2.5%
Answer:
-2.61803398875, -0.38196601125
or
(-3±√5)/2
Step-by-step explanation:
First, expand. (2x+3)² = 4x²+12x+9=5
4x²+12x+4 = 0
Quadratic equations take the form ax²+bx+c = 0
In this case,
a = 4
b = 12
c = 4
You can solve with the equation x=(-b±√b²-4ac)/2a
Plug in:
(-12±√144-64)/8
(-12±√80)/8
(-12±√2^4×5)/8
(-12±4√5)/8
(-3±√5)/2
Final answer x = (-3±√5)/2
If you want decimal form: -2.61803398875, -0.38196601125
Answer:
Since the null hypothesis is true, finding the significance is a type I error.
The probability of the year I error = level of significance = 0.05.
so, the number of tests that will be incorrectly found significant is computed as follow: 0.05 * 100 = 5
Therefore, 5 tests will be incorrectly found significant given that the null hypothesis is true.
It is -72 lol. that's pretty basic you know
