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Nikitich [7]
3 years ago
9

A meteorologist found that the rainfall in Lexington during the first half of the month was 1/2 of an inch. At the end of the mo

nth, he found that the total rainfall for the month was 7/12 of an inch. How much did it rain in the second half of the month?
Write your answer as a fraction or as a whole or mixed number.

Please answer ASAP
Mathematics
2 answers:
Makovka662 [10]3 years ago
6 0
It rained 1/12 of an inch
zalisa [80]3 years ago
3 0

Answer:

.1 inch or 1/12 of an inch

Step-by-step explanation:

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Can someone help me ASAP!!
Ede4ka [16]

Answer:

UR in trouble

Step-by-step explanation:

Look, the First order is the biggest force in the galaxy.

Now, it is gonna  send a star destroyer to ur house and blow it up.

5 0
3 years ago
Find the area of the polygon with vertices of A(2, 2), B(2, 7), C(8, 7),<br> and D(4, 2)
elena-s [515]

Answer:

<em>20 units²  </em>

Step-by-step explanation:

7 0
2 years ago
Students in 10th and 11th grade were asked whether they have a job. The raw data was converted to relative frequencies and recor
Softa [21]

Answer:

a)- Given that a student is a 10th grader, there is a 14% chance he or she has a job.

Step-by-step explanation:

Option (a) is correct here because Relative frequency means the probability of occurrence or number of time-specific event occurs to the total event.

Option (b) is not correct because We already know that student is in 10th or 11th grade, after that we get to know about 14% chance.

Option (c) & (d) are clearly not possible.

5 0
3 years ago
Read 2 more answers
Find the value x and write the property used here.
Serga [27]

Step-by-step explanation:

Soln,

Here,

45°+65°+y(let)=180°[ being a triangle]

or,110°+y=180°

or,y=180°-110°

so,y=70°

Now,

x=?

so,

x+y=180°[being straight angle]

or,x+70°=180°

or,x=180°-70°

x=110°

THEREFORE,x=110°

solved!

6 0
3 years ago
Read 2 more answers
Suppose that each observation in a random sample of 100 fatal bicycle accidents in 2015 was classified according to the day of t
liraira [26]

Answer:

The calculated χ² =  0.57   does not fall in the critical region χ² ≥  12.59  so we fail to reject the null hypothesis and conclude the proportion of fatal bicycle accidents in 2015 was the same for all days of the week.

Step-by-step explanation:

1) We set up our null and alternative hypothesis as

H0:  proportion of fatal bicycle accidents in 2015 was the same for all days of the week

against the claim

Ha:  proportion of fatal bicycle accidents in 2015 was not the same for all days of the week

2) the significance level alpha is set at 0.05

3) the test statistic under H0 is

χ²= ∑ (ni - npi)²/ npi

which has an approximate chi square distribution with ( n-1)=7-1=  6 d.f

4) The critical region is χ² ≥ χ² (0.05)6 = 12.59

5) Calculations:

χ²= ∑ (16- 14.28)²/14.28 + (12- 14.28)²/14.28 + (12- 14.28)²/14.28 + (13- 14.28)²/14.28 + (14- 14.28)²/14.28 + (15- 14.28)²/14.28 + (18- 14.28)²/14.28

χ²= 1/14.28 [ 2.938+ 5.1984 +5.1984+1.6384+0.0784 +1.6384+13.84]

χ²= 1/14.28[8.1364]

χ²= 0.569= 0.57

6) Conclusion:

The calculated χ² =  0.57   does not fall in the critical region χ² ≥  12.59  so we fail to reject the null hypothesis and conclude the proportion of fatal bicycle accidents in 2015 was the same for all days of the week.

b.<u> It is r</u>easonable to conclude that the proportion of fatal bicycle accidents in 2015 was the same for all days of the week

6 0
3 years ago
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