A sequence is defined by the following: an = 4n – 1 What is a1? What is a8?.

Mathematics

1 answer:

Lina20 [59]2 years ago

8 0

Answer:

A1= 3, A8 = 31

Step-by-step explanation:

an = a(#) so you plug the number with A into the formula 4n -1

4(1) - 1 = 4-1 = 3

4(8) - 1 = 32-1 = 31

You might be interested in

Leave answer in the simplest radical form.

slega [8]

$\cfrac{7x^{-\frac{3}{2}} ~~ y^{\frac{5}{2}} ~~ z^{-\frac{2}{3}}}{56 x^{-\frac{1}{2}} ~~ y^{\frac{1}{4}}}\implies \cfrac{7}{56}\cdot \cfrac{y^{\frac{5}{2}} ~~ y^{-\frac{1}{4}}}{x^{-\frac{1}{2}} ~~ x^{\frac{3}{2}} ~~ z^{\frac{2}{3}}}\implies \cfrac{1}{8}\cfrac{y^{\frac{5}{2}-\frac{1}{4}}}{x^{-\frac{1}{2}+\frac{3}{2}}~~ z^{\frac{2}{3}}}$

$\cfrac{y^{\frac{9}{4}}}{8x z^{\frac{2}{3}}}\implies \cfrac{\sqrt[4]{y^9}}{8x\sqrt[3]{z^2}}\implies \cfrac{\sqrt[4]{y (y^2)^4}}{8x\sqrt[3]{z^2}}\implies \cfrac{y^2 \sqrt[4]{y}}{8x\sqrt[3]{z^2}}$