The area of the arrow given in the figure is 610 square cm
<h3>Area of composite figure</h3>
The given figure is made up of rectangle and triangle. The area is expressed as:
Area = Area of rectangle + area of triangle
Substitute the given parameters
Area of the arrow = (15*20) + 0.5(31 * 20)
Area of the arrow = 300 + 310
Area of the arrow = 610 square cm
Hence the area of the arrow given in the figure is 610 square cm
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Answer:
d=2.25t
Step-by-step explanation:
The height of the tree to the nearest tenth of foot is 20.5 ft
<h3>Right angle triangle:</h3>
A right angle triangle has one of its angles as 90 degrees. The sides can be found using Pythagoras theorem.
The side of the base triangle can be found using Pythagoras theorem.
c² = a² + b²
c² = 9.2² + 5.8²
c² = 84.64 + 33.64
c = 10.9 ft
using similar triangle ratio,
5.8 / 10.9 = 10.9 / x + 5.8
5.8x = 118.81 - 33.64
x = 85.17 / 5.8
x = 14.6844827586
x = 14.7 ft
The height of the tree to the nearest foot is 14.7 + 5.8 = 20.5 ft
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<span>f(x) = –10
f(5)=-10
f=</span>-10 divided by 5
f=-2
Answer:
Sum: 34 + 17 = 51
Difference: 34 - 17 = 17
Step-by-step explanation:
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