All categories

3 years ago

SOMEONE HELP !!!!!!!!!!

Mathematics

1 answer:

dybincka [34]3 years ago

5 0

Answer:

q^12

Step-by-step explanation:

To raise a power to a power you multiply the powers together. That would be 6*2=12.

You might be interested in

A teacher gave his students the four graphs below. Which graph represents a geometric sequence?

VARVARA [1.3K]

The answer is

graph A

Hope this helps :)

3 0

3 years ago

Read 2 more answers

5x3 + 14x2 + 9x <br> help

Cerrena [4.2K]

<h3>Answer: x(x+1)(5x+9) </h3>

===================================================

Work Shown:

5x^3 + 14x^2 + 9x

x( 5x^2 + 14x + 9 )

To factor 5x^2 + 14x + 9, we could use the AC method and guess and check our way to getting the correct result.

A better way in my opinion is to solve 5x^2 + 14x + 9 = 0 through the quadratic formula

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(14)\pm\sqrt{(14)^2-4(5)(9)}}{2(5)}\\\\x = \frac{-14\pm\sqrt{16}}{10}\\\\x = \frac{-14\pm4}{10}\\\\x = \frac{-14+4}{10} \ \text{ or } \ x = \frac{-14-4}{10}\\\\x = \frac{-10}{10} \ \text{ or } \ x = \frac{-18}{10}\\\\x = -1 \ \text{ or } \ x = \frac{-9}{5}\\\\$

Then use those two solutions to find the factorization

x = -1 or x = -9/5

x+1 = 0 or 5x = -9

x+1 = 0 or 5x+9 = 0

(x+1)(5x+9) = 0

So we have shown that 5x^2 + 14x + 9 factors to (x+1)(5x+9)

-----------

Overall,

5x^3 + 14x^2 + 9x

factors to

x(x+1)(5x+9)

6 0

2 years ago

If i had to pay 3,500 dollars but I had a 69% off coupon for some reason how much would I have to pay also please show me how yo

zalisa [80]

Answer:

1085

Step-by-step explanation:

100 - 69 =31%

3500 /100 =35

35 x 31 = 1085

5 0

2 years ago

Read 2 more answers

If it costs $55 for 20 people to go rent a movie at red box how much does it cost per person?

marusya05 [52]

55/20 = 2.75
It costs $2.75 per person

4 0

2 years ago

Triangle ABC has the following coordinates: A (-2, 3) B (4, -3) C (-2, -3) What are the coordinates points for triangle A'B'C' i

lina2011 [118]

Answer:

A' (3/2, -9/4)

B' (-3, 9/4)

C' (3/2, 9/4)

Step-by-step explanation:

1. You have the following coordinates of the vertices of the triangle ABC:

A (-2, 3) B (4, -3) C (-2, -3)

2. The given scale factor is -3/4, therefore, to calculate the coordinates of the triangle A'B'C', you must multiply each coordinate of the triangle ABC by the scale factor.

3. Therefore, you obtain that the the coordinates of the triangle A'B'C' are:

A'=((-2)(-3/4), (3)(-3/4))=(3/2, -9/4)

B'=(4(-3/4), (-3)(-3/4))=(-3, 9/4)

C'=((-2)(-3/4), (-3)(-3/4))=(3/2, 9/4)

7 0

3 years ago