Question

If two-point charges, 2000 meters apart, have charge values of 40 C and -40 C, respectively, what is the value of the mutual force between them? (Coulomb's constant = 9.0 x 109 N•m2/C2).

Answer 1

Answer:

The value of the mutual force between them is 3.6 x 10⁶ N

Step-by-step explanation:

Given;

distance between the two-point charges, r = 2000 m

the value of the two-point charges, q₁ and q₂ = 40 C and -40 C

Coulomb's constant, k = 9 x 10⁹ Nm²/C²

The value of the mutual force between them is calculated by applying Coulomb's law;

$F = \frac{K|q_1|q_2|}{r^2} \\\\F = \frac{(9 \times 10^9)(40\times 40)}{(2000)^2} \\\\F = 3.6 \times 10^6 \ N$

Therefore, the value of the mutual force between them is 3.6 x 10⁶ N.