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kirza4 [7]
3 years ago
15

Help please and thank you !

Mathematics
1 answer:
blsea [12.9K]3 years ago
4 0
I can’t see it properly
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The 6th term of an Arithmetic Progression is 17 and the 13th term is 38. Determine the 19th term ​
Sonja [21]

Answer:

56

Step-by-step explanation:

The n th term of an AP is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₆ = 17 and a₁₃ = 38, then

a₁ + 5d = 17 → (1)

a₁ + 12d = 38 → (2)

Subtract (1) from (2) term by term to eliminate a₁

7d = 21 ( divide both sides by 7 )

d = 3

Substitute d = 3 into (1) and evaluate for a₁

a₁ + 5(3) = 17

a₁ + 15 = 17 ( subtract 15 from both sides )

a₁ = 2

Thus

a_{19} = 2 + (18 × 3) = 2 + 54 = 56

4 0
4 years ago
Which model can be used to show the correct product of 0.60 and 0.40?
snow_lady [41]
Last one bottom !!! :)
5 0
2 years ago
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Ava and her little sister, April, both have the same birthdays on the same day. Ava is 12 years old, April is nine years old. Di
const2013 [10]

Answer:

6 years ago

Step-by-step explanation:

12 - 6 = 6

9 - 6 = 3

3 * 2 = 6

4 0
4 years ago
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Forgot how to do this ​
kotykmax [81]

Answer:

Volume = π×32×6 = 169.64600329385 feet^3

Step-by-step explanation:

5 0
3 years ago
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I NEED THE ANSWER ASAP!! I WILL MARK BRAINLIEST!!
qaws [65]

Answer:

To find the line parallel to the line y = -2/3x + 1 and passing through the point (-6, -1), we will need to know that if two lines are parallel, then their slopes are equivalent to each other.

Since we are given the slope, we need to find the y-intercept of the line. We can find the y-intercept by substituting the point (-6, -1) into a new equation with the slope of m = -2/3. Remember that slope-intercept form is y = mx + b.

y = -2/3x + b (substitute the ordered pair)

-1 = -2/3(-6) + b

-1 = 4 + b (subtract 4 from both sides)

-5 = b

Therefore, the equation of the line passing through the point (-6, -1) and parallel to y = -2/3x + 1 is y = -2/3x - 5.

Step-by-step explanation:

7 0
3 years ago
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