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2 years ago

Please answer quickly, simple geometry

Mathematics

1 answer:

Maru [420]2 years ago

7 0

OPTION C IS THE CORRECT ANSWER.

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2 years ago

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Find the value of the missing side. Round your answer to the nearest hundredth

irina [24]

Answer:

let, missing angle be x,

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h²=p²+b²

x²=12²+16²

x²=144+256

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2 years ago

How many solution does each graph have

SVEN [57.7K]

Answer:

one solution 

no solution 

infinity solutions 

Step-by-step explanation:

A: If the graphs of the equations intersect, then there is one solution that is true for both equations.

B; If the graphs of the equations do not intersect (for example, if they are parallel), then there are no solutions that are true for both equations.

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3 years ago

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2 years ago

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Find the absolute maximum and minimum values of f(x,y)=xy−4x in the region bounded by the x-axis and the parabola y=16−x2.

skad [1K]

Answer:

The absolute maximum and minimum is $20\; \text{and} -20.$

Step-by-step explanation:

We first check the critical points on the interior of the domain using the

first derivative test.

$f_x=y-4=0$

$f_y=x=0$

The only solution to this system of equations is the point (0, 4), which lies in the domain.

$f_{xx}=0, \;f_{yy}=0\; \text{and}\; f_{xy}=-1$

$\Rightarrow f_{xx}f_{yy}-f_{xy}=o-1=-1$

$\therefore (0,4)$ is a saddle point.

Boundary points - $(4,0), (-4,0), (0,16)$

Along boundary $y=16-x^2$

$f=x(16-x^2)-4x$

$=16x-x^3-4x$

$\Rightarrow f^'=16-3x^2-4=0$

$\Rightarrow 3x^2=12$

$\Rightarrow x=\pm2,\;\;y=14$

Values of f(x) at these points.

$\begin{array}{}(4,0)=-16\\(-4,0)=16\\(0,16)=0\\(2,14)=20\\(-2,14)=-20\end{array}$

Therefore, the absolute maximum and minimum is $20\; \text{and} -20.$

6 0

3 years ago