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2 years ago

8

SOMEONE PLEASE HELP ME PLEASE

2 answers:

sukhopar [10]2 years ago

5 0

BDE=70
EDG=50
FDG=60
CDA=85

Andreas93 [3]2 years ago

4 0

Answer:

BDE – 70°

EDG – 50°

FDG – 60°

CDA – 85°

Step-by-step explanation:

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The equation r=3c +5 represents the values shown in the table below C- 6, 8, 12, 18 R- 23, 29, ?, 59 What is the missing value i

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The missing value is 53.

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Determine formula of the nth term 2, 6, 12 20 30,42

nalin [4]

Check the forward differences of the sequence.

If $\{a_n\} = \{2,6,12,20,30,42,\ldots\}$ , then let $\{b_n\}$ be the sequence of first-order differences of $\{a_n\}$ . That is, for n ≥ 1,

$b_n = a_{n+1} - a_n$

so that $\{b_n\} = \{4, 6, 8, 10, 12, \ldots\}$ .

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and we can solve for $b_n$ in terms of $b_1=4$ :

$b_{n+1} = b_n + 2$

$b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2$

$b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2$

and so on down to

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$a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)$

$a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))$

$a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))$

and so on down to

$a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2$

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2 years ago

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irinina [24]

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Step-by-step explanation:

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Marrrta [24]

When it says to estimate, I always think of doing it by hand to show work. So set it up like this:

96

<u>x 34</u>

So follow it out multiplying across 4*6 and 4*9 carrying over as needed to get it to look like this:

96

<u>x 34</u>

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Do the same for the 3 to get this:

96

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384

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Add 384+2880=3264

Your final answer is 3,264

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2 years ago