The complete version of question:
<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>
Answer:
Step-by-step explanation:
As the description of the statement is:
'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>
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As
- <em>Five times the sum of a number and 27 </em>is written as:

- <em>greater than or equal </em>is written as:

- <em>six times the sum of that number and 26' </em>is written as: 6(x + 26)
so lets combine the whole statement:
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solving
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Therefore,
Cant see it can yo take it above
19/5=p/3-36/5
Convert the decimals into fractions
15 x 19/5=(p/3-36/5) x 15
Multiply both sides by 15
57=5x-108
5x-108+108=57+108
Add 108 to both sides
5x=165
X=33
Answer
Hope this helps
1.0649 to the nearest thousandths is 1.065
You could get this by finding where the thousandths place is, which is the third number.
Now, look at the number to the right.
If it's 5 or higher, round up.
If it's 4 or lower, round down.
Since it is 9, we round up.
The 4 turns into a 5.
So, 1.065
Hope I helped!