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Ganezh [65]
4 years ago
13

Which table should be used to graph the function shown above?

Mathematics
1 answer:
poizon [28]4 years ago
6 0

Answer:

The table should include the following values for x:

-4 , -3, -2, -1, 0, 1

And the values for y should be:

-5, -3, -1, 1, 3, 5

Step-by-step explanation:

In order to map these just look for the places where the line crosses the grid lines. Then use the x values for the x table and the y values for the y table.

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F(x) = 2x – 1 g(x) = 7x – 12 What is h(x) = f(x) + g(x)?
melomori [17]
h(x)= 9x - 13

This is because when you add 2x and 7x you get 9 x and -1 - 12 equals -13 making 9x - 13.
4 0
3 years ago
Which of the following shows the extraneous solution to the logarithmic equation below?
Gemiola [76]

Answer:

x=4

Step-by-step explanation:

log5(x+1)=1, (x+1)=5, x=4

3 0
3 years ago
For what value of c is the relation a function?
nydimaria [60]

Answer:

{ c  ∣  c ≠  2 , 12, -1, 0, c ∈ R }

Step-by-step explanation:

Considering the set

\left\{\left(2,\:8\right),\left(12,\:3\right),\:\left(c,\:4\right),\:\left(-1,\:8\right),\:\left(0,\:3\right)\right\}

As we know that

  • A function is said to be a relation if every x-value has one and only one y-value.

So, the value of c must not be equal to 2, 12, -1, 0 i.e. c ≠ 2, 12, -1, 0

Therefore,

                   { c  ∣  c ≠  2 , 12, -1, 0, c ∈ R }

7 0
3 years ago
Which number is the least prime number: 0, 1, 2, or 3?
Alinara [238K]
1 is the least prime number
5 0
4 years ago
Read 2 more answers
Find the x-value for point C such that AC and BC from a 2:3 ratio.
Galina-37 [17]

Given:

Point C divides AB such that AC:BC=2:3.

To find:

The x-value for point C.

Solution:

Section formula: If a point divide a line segment in m:n, then

Point=\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)

Form the given graph it is clear that the endpoints of the line segment AB are A(-3,5) and B(3,0).

Point C divides AB such that AC:BC=2:3. Using section formula, the coordinates of point C are

C=\left(\dfrac{2(3)+3(-3)}{2+3},\dfrac{2(0)+3(5)}{2+3}\right)

C=\left(\dfrac{6-9}{5},\dfrac{0+15}{5}\right)

C=\left(\dfrac{-3}{5},\dfrac{15}{5}\right)

C=\left(-0.6,3\right)

The x-value of C is -0.6.

Therefore, the correct option is B.

6 0
3 years ago
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