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3 years ago

I NEED HELL PLZ I don’t get it i need to turn it soon.

Mathematics

2 answers:

Blababa [14]3 years ago

7 0

60% of the class is blonde

Alona [7]3 years ago

3 0

1why2

2does3

3your4

4teacher5

5use6

6googl6e7

7forms?8

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Marguerite answered 79% of the questions on her test correctly. What fraction of the questions did she answer correctly?

djyliett [7]

Answer:

79 of the questions were right/coreect

Step-by-step explanation:

if you have 100 quesions and you get 79% done and correct then you did 79 answers right

3 0

3 years ago

Fill in the table using this function rule

goldenfox [79]

When x=3, y=9 and when x=6, y=3 bc u plug them into the equation

8 0

3 years ago

Please help on these 2 questions.

Law Incorporation [45]

Answer:

1. 8.75

2. 3.48

Step-by-step explanation:

hope this helps :3

6 0

3 years ago

Read 2 more answers

use the five step plan to solve the word problem. Show all five steps in youre response. doug is twice anns age. doug is 34 year

vovangra [49]

The answer is anne is 17. You would need to right the correct equation 34=2x. X is anne's age. Then you would divide both sides by 2 (really just divide 34 by 2). 34/2=17.

3 0

3 years ago

The first two terms of a sequence are 5 and 7. Each term after the second is found by taking the average (arithmetic mean) of al

ch4aika [34]

Answer:

Step-by-step explanation:

We can prove that every number after the second will be a six by induction.

Base case. Since $\frac{5 + 7}{2} = 6$ , so the third term is a six.

Inductive hypothesis. Fix the number of terms to be n and assume that

$\frac{1}{n} \sum\limits_{i=1}^{n}t_i = 6$

Inductive step. We will now show that $\frac{1}{n+1} \sum\limits_{i=1}^{n+1}t_i = 6$ .

Notice that

$\begin{array}{lll}\frac{1}{n+1} \sum\limits_{i=1}^{n+1}t_i & = \frac{n}{n(n+1)} \sum\limits_{i=1}^{n+1}t_i & \\& = \frac{t_{n+1}}{n+1} + \frac{n}{n(n+1)} \sum\limits_{i=1}^{n}t_i &\\& = \frac{t_{n+1}}{n+1} + \frac{6n}{n+1} & \text{(by the IH)}\\& = \frac{6}{n+1} + \frac{6n}{n+1} & \text{by de\\finition}\\& = \frac{6(n+1)}{n+1} & \\& = 6 & \end{array} \square$

6 0

3 years ago