Pairs, in this case, relates to a group of 2 or more. We have 6 friends. Let's call them A,B,C,D,E,F. This will allow us to make a [some sort of] combination tree:
1. ABC against DEF
2. ABD against CEF
3. ABE against CDF
4. ABF against CDE
5. ACD against BFE
6. ACE against BDF
7. ACF against BDE
8. ADE against BCF
9. ADF against BCE
10. AEF against BCD
I believe there are 12 combinations... I just can't think of the last 2 though.
Answer: 10
you have to find a common denominator between two and five which is 10. therefore making the number 2 into the fraction 20/10 and finding the common denominator of 1/5 makes it now 2/10. now divide 20 by 2 which gets you 10. and dividing 10 by 10 gets you. therefore making the new fraction 10/1 which is equal to 10. :)
Just convert the kilometers
Answer:
As the wheel makes this 270 degree counterclockwise rotation about the origin, the y-coordinate of the first car decreases from 80 to 0 and then further from 0 to -80, and finally increases to 0.
The x-coordinate decreases from 0 to -80 and then increases to 0; from there it increases further to 80.
Thus, the coordinates of the first car, after this 270-degree rotation, are (80, 0).
