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koban [17]
2 years ago
10

Say that the economy is in a recession, causing vehicle prices to drop by eight percent. If your car was previously worth $25,29

5, what is it worth now, to the nearest dollar? a. $23,851 b. $23,421 c. $23,271 d. $22,133​
Mathematics
2 answers:
qaws [65]2 years ago
8 0

Answer:

c.

$23,271

Step-by-step explanation:

i took the same test on edg

timama [110]2 years ago
8 0

Answer:

c

Step-by-step explanation:

follow my twitter pichu_the_republican

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Is. 36yd2ft bigger than 114ft 2in
Zarrin [17]
NO! 
1 yd=3 ft
36*3=108
108+2=110
114>110, therefore no
5 0
3 years ago
The graph of the function y = x² - x - 2 is shown below.
velikii [3]
Y=(x+1)(x-1) this is factored out
5 0
3 years ago
PLS HELP ME !!!!<br> The last one is (x+2)^2 + (y-1) ^2 = 12
ladessa [460]

Answer:

its the first one or the last one

Step-by-step explanation:

i got the same thing on the graph sry

7 0
3 years ago
A scientist had 3/4 of a bottle of a solution. She used 1/6 of the solution in a experiment. How much of the bottle didi she use
Rashid [163]

Answer:

1/8

Step-by-step explanation:

1/6 × 3/4

Multiply across top, then bottom

1×3=3

6×4=24

Then reduce if necessary.

3/24

Divide top and bottom by 3

3÷3=1

24÷3=8

You should get 1/8

5 0
3 years ago
Semicircles
Studentka2010 [4]

Answer:

The area of the shaded portion of the figure is 9.1\ cm^2

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The shaded area is equal to the area of the square less the area not shaded.

There are 4 "not shaded" regions.

step 1

Find the area of square ABCD

The area of square is equal to

A=b^2

where

b is the length side of the square

we have

b=4\ cm

substitute

A=4^2=16\ cm^2

step 2

We can find the area of 2 "not shaded" regions by calculating the area of the square less two semi-circles (one circle):

The area of circle is equal to

A=\pi r^{2}

The diameter of the circle is equal to the length side of the square

so

r=\frac{b}{2}=\frac{4}{2}=2\ cm ---> radius is half the diameter

substitute

A=\pi (2)^{2}

A=4\pi\ cm^2

Therefore, the area of 2 "not-shaded" regions is:

A=(16-4\pi) \ cm^2

and the area of 4 "not-shaded" regions is:

A=2(16-4\pi)=(32-8\pi)\ cm^2

step 3

Find the area of the shaded region

Remember that the area of the shaded region is the area of the square less 4 "not shaded" regions:

so

A=16-(32-8\pi)=(8\pi-16)\ cm^2  

---> exact value

assume

\pi =3.14

substitute

A=(8(3.14)-16)=9.1\ cm^2

8 0
3 years ago
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