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Len [333]
2 years ago
7

Find the value of x.

Mathematics
2 answers:
DanielleElmas [232]2 years ago
7 0

Answer:

x = -7

Step-by-step explanation:

Make an equation:

3x + 33 = 12

3x = -21

x = -7

zalisa [80]2 years ago
3 0

Answer:

x = -7

Step-by-step explanation:

form an equation.

14 + x + 2x + 19 = 12

like terms together;

x + 2x = 12 - 14 - 19

simplify;

3x = -21

divide both sides by 3;

x = -7

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Identify the solution(s) of v2+11v−26=0.
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Answer:

i solved for v and got

v = 2, -13

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3 years ago
A clock was reading the time accurately on Friday at noon. On Monday at 6pm the clock was running late by 468 seconds. On averag
Setler [38]

The clock was skipping 3 seconds every 30 minutes from Friday noon to Monday 6 pm.

The clock was still accurate by Friday noon. The clock was late by 468 seconds by Monday, 6 pm.

To solve the problem, we must:

Know how many 30-minutes have passed during the time period.

1 day = 24 hours

1 hour = 60 minutes = 2 × (30 minutes)

1 day = 24 hours × 2 × (30 minutes)

1 day = 48 × (30 minutes)

Thus, there are 48, 30-minutes in a day. On Friday, however, we start counting at noon, which is half of the day. Moreover, on Monday, the mark is only up to 6 pm, which is three-fourths of the day.

Friday = 48 × \frac{1}{2} = 24

Saturday = 48

Sunday = 48

Monday = 48 × \frac{3}{4} = 36

TOTAL = 24 + 48 + 48 + 36 = 156

Therefore, the total number of 30-minutes that have passed is 156. There were 156, 30-minutes that passed during the time period.

Divide the number of total seconds late by the number of 30-minutes passed.

That is, the number of total seconds late= 468 seconds ÷ 156

= 3 seconds  

Therefore, the clock was skipping 3 seconds every 30 minutes from Friday noon to Monday 6 pm.

To learn more about clock problems visit:

brainly.com/question/27122093.

#SPJ1

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Louis traveled 2,795 on an airplane from
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Louis traveled 7,144 miles

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