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Sergio039 [100]
3 years ago
11

Write an equation for the quadratic graphed below

Mathematics
2 answers:
VladimirAG [237]3 years ago
8 0

Answer:

y = \frac{3}{2} x² - \frac{3}{2} x - 3

Step-by-step explanation:

uranmaximum [27]3 years ago
6 0

Answer:

Step-by-step explanation:

LOL The graph doesn’t match the y intercept :)

Anyway

If we have point (0,-3) we have a quadratic of

y=ax^2+bx-3 we are given points (-1,0) and (2,0) so

a-b-3=0 and 4a+2b-3=0

4a+2b-3+2(a-b-3)=0

4a+2b-3+2a-2b-6=0

6a-9=0

6a=9

a=1.5, since a-b=3

1.5-b=3

b=-1.5

y=1.5x^2-1.5x-3

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