Answer:
The maximum possible error of in measurement of the angle is 
Step-by-step explanation:
From the question we are told that
The angle of elevation is 
The height of the tree is h
The distance from the base is D
h is mathematically represented as
Note : this evaluated using SOHCAHTOA i,e

Generally for small angles the series approximation of 

So given that 


=> 
Now from the question the relative error of height should be at most
%
=> 
=> 
=> 
So for 

substituting values
![d [\frac{\pi}{12} ] = \pm \frac{[\frac{\pi}{12} ] + \frac{[\frac{\pi}{12} ]^3 }{3} }{1+ [\frac{\pi}{12} ] ^2} * \ p](https://tex.z-dn.net/?f=d%20%5B%5Cfrac%7B%5Cpi%7D%7B12%7D%20%5D%20%20%3D%20%20%5Cpm%20%20%5Cfrac%7B%5B%5Cfrac%7B%5Cpi%7D%7B12%7D%20%5D%20%2B%20%20%5Cfrac%7B%5B%5Cfrac%7B%5Cpi%7D%7B12%7D%20%5D%5E3%20%7D%7B3%7D%20%7D%7B1%2B%20%5B%5Cfrac%7B%5Cpi%7D%7B12%7D%20%5D%20%5E2%7D%20%2A%20%20%20%20%5C%20p)
=> 
Converting to degree


It’s 4/25 because 2/5 times 2/5 the numerator is 2 times 2 which is four and the denominator is 5 times 5 which is 25
Answer:
Step-by-step explanation:
-a + 6b = -3 + 6 * (-6) = -3 - 36 = -39
Answer:
No
Step-by-step explanation:
According to the property of the triangle ,
sum of any two sides should we greater then third side of the triangle.
Here, Measurement of three sides are given as 3,3,5 .
So, sum of the measurement of first two sides is 6.
And third side equals 10.
Clearly 6 is less than 10. So . it violates the property sum of any two sides should we greater then third side of the triangle.
Thus , Sides of a triangle can't be 3,3,10.
Answer:
The whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square is 6 ft
Step-by-step explanation:
Here we are required find the size of the sides of a dunk tank (cube with open top) such that the surface area is ≤ 160 ft²
For maximum volume, the side length, s of the cube must all be equal ;
Therefore area of one side = s²
Number of sides in a cube with top open = 5 sides
Area of surface = 5 × s² = 180
Therefore s² = 180/5 = 36
s² = 36
s = √36 = 6 ft
Therefore, the whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square = 6 ft.