All categories

2 years ago

Using the given zero, 2 - 4i, find one other zero of f(x) = x4 - 4x3 + 21x2 - 4x + 20

Mathematics

1 answer:

Effectus [21]2 years ago

4 0

For polynomials, complex zeros always come in conjugate pairs.

So if 2-4i is a zero of the given polynomial,

then 2+4i must be another.

You might be interested in

Which is the graph for this system {y=−x+4 {y=x−2

Karo-lina-s [1.5K]

Here is the screenshot of the graph.

8 0

3 years ago

2143.57333 whole number

poizon [28]

Answer:

No, this is not a whole number. See how it has a decimal point? That's how you know if it is a decimal.

4 0

2 years ago

-3 + 12x^2 + 3x - 5x^2 + 2x + 6 =

-Dominant- [34]

ANSWERRRRR :7x^2+5x+3

7 0

2 years ago

Read 2 more answers

An angle measures 3pi/4 radians. What is this angle's measure, in degrees?

Annette [7]

Answer:

135°

Step-by-step explanation:

To convert from radian measure to degree measure

degree measure = radian measure × $\frac{180}{\pi }$ , so

degree = $\frac{3\pi }{4}$ × $\frac{180}{\pi }$

Cancel π on numerator/denominator and 4, 180 by 4, leaving

degree = 3 × 45 = 135°

5 0

2 years ago

Read 2 more answers

Here is a triangular pyramid and its net.

bazaltina [42]

Answer:

a) Area of the base of the pyramid = $15.6\ mm^{2}$

b) Area of one lateral face = $24\ mm^{2}$

c) Lateral Surface Area = $72\ mm^{2}$

d) Total Surface Area = $87.6\ mm^{2}$

Step-by-step explanation:

We are given the following dimensions of the triangular pyramid:

Side of triangular base = 6mm

Height of triangular base = 5.2mm

Base of lateral face (triangular) = 6mm

Height of lateral face (triangular) = 8mm

a) To find Area of base of pyramid:

We know that it is a triangular pyramid and the base is a equilateral triangle. $\text{Area of triangle = } \dfrac{1}{2} \times \text{Base} \times \text{Height} ..... (1)\\$

${\Rightarrow \text{Area of pyramid's base = }\dfrac{1}{2} \times 6 \times 5.2\\\Rightarrow 15.6\ mm^{2}$

b) To find area of one lateral surface:

Base = 6mm

Height = 8mm

Using equation (1) to find the area:

$\Rightarrow \dfrac{1}{2} \times 8 \times 6\\\Rightarrow 24\ mm^{2}$

c) To find the lateral surface area:

We know that there are 3 lateral surfaces with equal height and equal base.

Hence, their areas will also be same. So,

$\text{Lateral Surface Area = }3 \times \text{ Area of one lateral surface}\\\Rightarrow 3 \times 24 = 72 mm^{2}$

d) To find total surface area:

Total Surface area of the given triangular pyramid will be equal to Lateral Surface Area + Area of base

$\Rightarrow 72 + 15.6 \\\Rightarrow 87.6\ mm^{2}$

Hence,

a) Area of the base of the pyramid = $15.6\ mm^{2}$

b) Area of one lateral face = $24\ mm^{2}$

c) Lateral Surface Area = $72\ mm^{2}$

d) Total Surface Area = $87.6\ mm^{2}$

3 0

2 years ago